Compute the Wronskian & Simplify

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    Simplify Wronskian
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Discussion Overview

The discussion revolves around computing the Wronskian of two functions, $y_1 = t^2 + 1$ and $y_2 = 3t^2 + k$, and determining the values of $k$ for which these functions are linearly independent. The scope includes mathematical reasoning and exploration of linear independence in the context of differential equations.

Discussion Character

  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant computes the Wronskian and suggests it is non-zero, indicating linear independence, but expresses confusion about the implications for $k$.
  • Another participant proposes that the functions are linearly independent as long as $k > 0$.
  • Further clarification is provided that the Wronskian being non-zero implies linear independence, but the specific values of $k$ are still in question.
  • One participant states that the functions are infinitely differentiable and calculates their derivatives, leading to a suggestion that $k$ can take any value except when $k = 3$.
  • Another participant reiterates the concern about the Wronskian being zero when $k = 3$, suggesting that $k$ can be any value except for this case.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the specific values of $k$ that maintain linear independence, with some suggesting $k > 0$ and others indicating that $k$ can be any value except for $k = 3$. The discussion remains unresolved regarding a definitive conclusion on the values of $k.

Contextual Notes

There are unresolved assumptions regarding the implications of the Wronskian being zero and the conditions under which linear independence is determined. The discussion does not clarify the full range of values for $k$ that would maintain linear independence.

shamieh
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Compute the Wronskian and simplify.
So the first part was easy

a) $y_1 = t^2 + 1$ , $y_2 = 3t^2 + k$

=$6t-2kt$

b) for what values of $k$ are the functions linearly independent

so would I just solve for $k$? I'm confused

What exactly does linearly independent mean?
 
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Ok so I figured out it is Linearly independent because after I took the Wronskian I didn't get 0. But for what values of $k$ ? Would it just be as long as $k > 0$ ?
 
You can use the Wronskian to show linear independence as follows: if the Wronskian is not identically zero, and the two functions are (infinitely) differentiable, then the two functions are linearly independent. For what values of $k$ does this happen?
 
Ackbach said:
You can use the Wronskian to show linear independence as follows: if the Wronskian is not identically zero, and the two functions are (infinitely) differentiable, then the two functions are linearly independent. For what values of $k$ does this happen?
as long as $k$ > 0 ?
 
the two functions are inifnitely differentiable

because $y_1 = t^2 + 1 $

'= 2t + 1
'' = 2
''' = 0
''''=0
...etc

and $y_2 = 3t^2 + k$
' = 6t
'' = 6
''' = 0
etc

So would it be all values as long as $k \ne 3$
 
Last edited:
wait so how about

t(6-2k) when k = 3 then t(6-6) = 0?

so would it be k can be any value except when k is 3?
 
shamieh said:
wait so how about

t(6-2k) when k = 3 then t(6-6) = 0?

so would it be k can be any value except when k is 3?

You got it!
 

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