Compute Unit Normal Vector: Why Derivative is Orthogonal

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 4K views
lordkelvin
Messages
21
Reaction score
0
The unit normal vector N of a given curve is equal to the first derivative with respect to t of the unit tangent vector T'(t)divided by the norm of T'(t) (For a parametric vector equation of parameter t.)

I realize this works because T(t) is orthogonal to T'(t), but I don't understand why the derivative of the vector T is orthogonal to T itself.

Can anyone explain to me why the derivative of a tangent vector is orthogonal to the tangent vector? Thanks.
 
Physics news on Phys.org
lordkelvin said:
Can anyone explain to me why the derivative of a tangent vector is orthogonal to the tangent vector? Thanks.

In general it is not true but if the tangent vectors have constant length then the derivative of the length is zero.