Computing Inner Products of Vectors: a,b,c,d,e,f

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The discussion focuses on computing inner products of vectors a, b, c, d, e, and f, given specific inner product values: <a,b> = -4, <a,c> = -9, and <b,c> = 2. The relationships between the vectors are defined as d = b + c, e = -4a + 3b, and f = -4b + 5c. Participants emphasize the use of the properties of inner products, specifically symmetry and linearity, to derive the required inner products <b,a>, <a,d>, <e,c>, and <a,f>.

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alkhaldi20
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Hi everyone,

I need help with this problem. I just can't get it:

Let a,b,c,d,e and f be vectors such that \langle a,b \rangle=-4, \quad \langle a,c \rangle=-9, \quad \langle b,c \rangle=2, \quad b+c=d, \quad -4 a+3 b=e and -4 b+5 c=f. Compute the following inner products:

\langle b,a \rangle=
\langle a,d \rangle=
\langle e,c \rangle=
\langle a,f \rangle=
 
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Which question are you having trouble with? You have to apply the fact that the inner product is symmetric and linear in each argument. That is, for all vectors u, v, and w and all scalars a, we have:
[tex] \langle u, v\rangle = \langle v, u\rangle[/tex]
and
[tex] \langle au + v, w\rangle = a\langle u, w\rangle + \langle v, w\rangle[/tex]
 
alkhaldi20 said:
Hi everyone,

I need help with this problem. I just can't get it:

Let a,b,c,d,e and f be vectors such that [tex]\langle a,b \rangle=-4, \quad \langle a,c \rangle=-9, \quad \langle b,c \rangle=2, \quad b+c=d, \quad -4 a+3 b=e\ and -4 b+5 c=f\,.\[/tex]

Compute the following inner products:

[tex]\langle b,a \rangle=[/tex]
[tex]\langle a,d \rangle=[/tex]
[tex]\langle e,c \rangle=[/tex]
[tex]\langle a,f \rangle=[/tex]
I put the [tex]\left[\text{tex}\right]\left[\text{/tex}\right][/tex] tags in for you.

[tex]\langle a,d \rangle=\langle a,b+c \rangle=\langle a,b \rangle+\langle a,c \rangle=\,[/tex] etc.
 
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