Computing the second virial coefficient

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 3K views
JD_PM
Messages
1,125
Reaction score
156

Homework Statement



Screenshot (48).png


##b_2## is the second virial coefficient

Homework Equations



Virial expansion:

$$P = nkT(1 + b_2 (T)n + b_3 (T)n^2...)$$

$$b_2 = -\frac{1}{2} \int dr f(r) $$

r is the distance vector.

$$f(r) = e^{-\beta \phi(r)} - 1$$

The Attempt at a Solution



$$b_2(T) = 2 \pi r^2 \int_0^{\sigma} (e^{-\beta \phi(r)} - 1 )dr = 2\pi \int_0^{\sigma} r^2 dr - 2\pi \int_0^{\sigma} r^2 e^{-\beta \phi(r)} dr$$

I solved these integrals but did not get the stated comparison with VdW model. Am I going OK? I can post more algebraic steps.
[/B]
 

Attachments

  • Screenshot (48).png
    Screenshot (48).png
    19.1 KB · Views: 1,477
Physics news on Phys.org
In step 3, the limuts of your integral need to be from ## \sigma ## to ## +\infty ##, with ## \phi(r)=-\frac{\epsilon}{r^6} ##. For the integral from ## 0 ## to ## \sigma ##, the ## - 1 ## term will give ## -\sigma ##. ## \\ ## It's not completely clear what you are doing though. The ## b_2 ## as you have it written must be integrated over ## dv=4 \pi r^2 \, dr ## if you are getting a ## 4 \pi r^2 ## from it. ## \\ ## Edit: Yes, I googled it, and it is ## dv ##. ## \\ ## See equations 47-53 of this "link" that I googled: http://www.nyu.edu/classes/tuckerman/pchem/lectures/lecture_4.pdf ## \\ ## This one is too difficult to expect a student to derive on their own, so I am providing you with the solution here.
 
Last edited:
  • Like
Likes   Reactions: JD_PM
Thank you, this document is really helpful! I got the expressions for a and b!
 
  • Like
Likes   Reactions: Charles Link