Computing the second virial coefficient

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Homework Help Overview

The discussion revolves around the calculation of the second virial coefficient, denoted as ##b_2##, within the context of the virial expansion in thermodynamics. The original poster presents equations related to the virial expansion and attempts to compute ##b_2## using integrals involving the potential energy function ##\phi(r)##.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to compute ##b_2(T)## through integration but expresses uncertainty about the limits of integration and the comparison with the Van der Waals model. Some participants question the limits of the integral and the form of the potential function used, suggesting that the integration should be over a different range.

Discussion Status

Participants are actively engaging with the original poster's approach, providing clarifications and corrections regarding the integration limits and the form of the equations. There is acknowledgment of helpful resources shared, but no consensus has been reached regarding the correct method or outcome.

Contextual Notes

There are indications of potential confusion regarding the integration limits and the setup of the problem, as well as references to external resources that may not be universally accessible to all participants.

JD_PM
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Homework Statement



Screenshot (48).png


##b_2## is the second virial coefficient

Homework Equations



Virial expansion:

$$P = nkT(1 + b_2 (T)n + b_3 (T)n^2...)$$

$$b_2 = -\frac{1}{2} \int dr f(r) $$

r is the distance vector.

$$f(r) = e^{-\beta \phi(r)} - 1$$

The Attempt at a Solution



$$b_2(T) = 2 \pi r^2 \int_0^{\sigma} (e^{-\beta \phi(r)} - 1 )dr = 2\pi \int_0^{\sigma} r^2 dr - 2\pi \int_0^{\sigma} r^2 e^{-\beta \phi(r)} dr$$

I solved these integrals but did not get the stated comparison with VdW model. Am I going OK? I can post more algebraic steps.
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In step 3, the limuts of your integral need to be from ## \sigma ## to ## +\infty ##, with ## \phi(r)=-\frac{\epsilon}{r^6} ##. For the integral from ## 0 ## to ## \sigma ##, the ## - 1 ## term will give ## -\sigma ##. ## \\ ## It's not completely clear what you are doing though. The ## b_2 ## as you have it written must be integrated over ## dv=4 \pi r^2 \, dr ## if you are getting a ## 4 \pi r^2 ## from it. ## \\ ## Edit: Yes, I googled it, and it is ## dv ##. ## \\ ## See equations 47-53 of this "link" that I googled: http://www.nyu.edu/classes/tuckerman/pchem/lectures/lecture_4.pdf ## \\ ## This one is too difficult to expect a student to derive on their own, so I am providing you with the solution here.
 
Last edited:
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See the additions in post 2 above.
 
Thank you, this document is really helpful! I got the expressions for a and b!
 
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