Concavity of a function: y=2/3x^3-x^2+3x+5

[Hollysmoke]

I just wanted to make sure I did this right:

y=2/3x^3-x^2+3x+5
y’=2x^2-2x+3
y’’=4x-2
=2(2x-1)


2x-1=0
2x=1
x=1/2

And then I substitute x into the original equation to find the IP, right?

 

[0rthodontist]

Yes, that's correct.