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Homework Help: Concavity of a function: y=2/3x^3-x^2+3x+5

  1. Jun 27, 2006 #1
    I just wanted to make sure I did this right:

    y=2/3x^3-x^2+3x+5
    y’=2x^2-2x+3
    y’’=4x-2
    =2(2x-1)


    2x-1=0
    2x=1
    x=1/2

    And then I substitute x into the original equation to find the IP, right?
     
  2. jcsd
  3. Jun 27, 2006 #2

    0rthodontist

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    Science Advisor

    Yes, that's correct.
     
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