Concept of 3 balls falling from building at different angles

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Discussion Overview

The discussion revolves around the dynamics of three balls thrown from a height at different angles: upwards, horizontally, and downwards. Participants explore the relationship between initial velocities, gravitational potential energy, and the final velocities of the balls upon reaching the ground, considering various assumptions such as neglecting air resistance.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant suggests that all balls will reach the ground with the same final velocity due to equal initial gravitational potential energy, assuming they are launched with the same initial speed.
  • Another participant agrees, affirming that if the initial speeds are the same, the conclusion holds true.
  • A different participant challenges this by emphasizing the importance of the launch angles and initial velocities, providing calculations for each case and concluding that they all hit the ground with the same speed under the same initial conditions.
  • One participant notes that the ball thrown upwards returns to the original launch point with the same speed downwards, linking this to the conservation of energy principle.
  • Another participant raises a point about the curvature of the Earth, questioning whether it becomes significant at higher speeds and suggesting that escape velocity could alter the outcome.
  • A later reply acknowledges the complexity of the problem and expresses a newfound understanding of the concepts discussed.

Areas of Agreement / Disagreement

Participants generally agree that if the balls are launched with the same initial speed, they will hit the ground with the same final speed. However, there are competing views regarding the effects of launch angles, initial velocities, and the significance of Earth's curvature, indicating that the discussion remains unresolved in these areas.

Contextual Notes

Participants assume ideal conditions by neglecting air resistance and other real-world factors. The discussion also touches on the implications of varying launch angles and speeds, which may affect the outcomes under different conditions.

mrbrownstone
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If a ball is thrown upwards, another straight out, and another downwards, which will reach the ground with the highest velocity? After thinking about this for a while my conclusion is that they all will have the same velocity since they all have the same initial gravitational potential energy. Am I on the right track?
 
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Yes. Assuming they all are given the same initial speed, you are correct.
 
Thank you very much for the input. I'm glad I found this forum, it seems to be an excellent resource.
 
No ha ha
It depends on what velocitys they are being launched at, and I am assuming that you are neglecting friction.
So let's say they all have the same initial velocities and start at 50 meters up. The starting velocities are 10m/s.
Vertical Launch: So we must first find out how high it goes before it stops and then starts heading back down to earth. I have calculated using the formula H(height)= Vi(initial veritcal velocity)T(time)+1/2(-9.8[acceleration due to gravity])(T2) here it is without the writing H=Vi*T-1/2*(9.8)*T2... I got that it reached 55.102 meters. The using PE=KE i got that it will have a speed of 32.863 m/s

Horizontal launch: So here it gets complicated but i will give you two answers, first its overall velocity cause it will have both an X-axis component, its initial veloctiy, and a Y-axis component. The second is just the Y-axis part. So I use the equation 2HG(acceleration due to gravity)= Vfinal2-Vinitial2 to find the final vertical velocity. And i get 31.305 m/s. Thats just the Y-axis componet. the overall speed is 32.863 m/s

Straight down launch: I will use the same method as Horizontal launch to find the final velocity here. (use same formula) and i get that the final speed is 32.863...

Im a little bit shocked at what I am getting but all my numbers are correct. So it seems that yes they will all hit the ground with the same speed... That is that they have all been launched at the same initial speed

This is kinda cool and weird to me ha ha, Hope this answers your question
 
:smile: Nice
 
One thing that could have been noted, that for the ball thrown upwards, eventually it returns back to the point from where it was thrown from, with the same speed, but now downwards, so it should be clear that the upwards and downwards case is the same.

The horizontal case isn't so obvious unless you take into account that the total energy, KE + GPE is the same as the upwards and downwards case. This assumes that the object's speed isn't fast enough that curvature of the Earth's surface would be significant.
 
Jeff Reid said:
This assumes that the object's speed isn't fast enough that curvature of the Earth's surface would be significant.
Uh, really?
 
cesiumfrog said:
Uh, really?

well yeah, if you threw it hard enough it would never hit the ground as it would reach escape velocity (I know its not being thrown in the most efficient direction to exit the Earth's pull but it still has a Z component meaning it can be done with enough force)

I think you are looking at a lot of decimal ponts before it's a factor in the real world, but it's worth mentioning
 
Wow... at first I was very confused, now I get it. Interesting problem!
 

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