Concept with Maxwell-Boltzmann Distribution Curve

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The Maxwell-Boltzmann distribution illustrates the range of particle energies in gases, represented graphically to show the number of particles at various energy levels. This distribution is linked to definite integration, as it helps calculate the density of states (DOS), which indicates the closeness of electronic energy levels. A high DOS signifies many energy levels within a specific interval, allowing integration to determine the total number of particles in that range. The discussion also clarifies that the distribution applies to three-dimensional particle velocities, emphasizing the integration over all velocity components to find particle density. Understanding these concepts is crucial for analyzing the effects of defects in materials like crystals.
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In any system, the particles present will have a very wide range of energies. For gases, this can be shown on a graph called the Maxwell-Boltzmann distribution, which is a plot of the number of particles having various energies. The area under the curve is a measure of the total number of particles present.

Does this have something to do with definite integration?
 
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Yes, The Maxwell Boltmann distribution (for classical particles) or more generally the Boltzmann distribution denotes the socalled "density of states (DOS)". This quantity expresses how close consecutive electronical energylevels are spearated from each other. High DOS means many energylevels in an energy-interval [E, E+dE]. If you integrate over this interval (this is a definite integration indeed) you get the total number of particles (ie electrons) in that specific energy interval.

The DOS and PDOS (partial DOS) are very important quantities for studying the influence of defects (like missing atoms in crystals) onto the electrostatics of many particle bodies like crystals.

regards
marlon
 
Yes, it does. Whoever you are quoting there, however, only had the 1-dimensional distribution in mind. In fact, the Maxwell-Boltzmann distribution applies also to a collection of particles with velocities in three dimensions. The integrations are over all velocities so that if f(v) is the distribution function then

\int f(\vec v) dv_x dv_y dv_z = n

is the number density of particles in real space. Strictly speaking, it is not an area. Generally, f = f(\vec x, \vec v, t) allowing for both temporal and spatial variation of the distribution function.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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