Conceptual Heat X-fer Question (Steady state, liquid changing temp as it flows)

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SUMMARY

The discussion focuses on the heat transfer in a tube where a liquid flows at a steady state, with the inner wall maintained at a constant temperature (Ts). The heat transfer rate is defined by the equation q=h (π D L)((Ts−Tw1)−(Ts−Tw2))/ln((Ts−Tw1)(Ts−Tw2)). Participants clarify the derivation of this equation, emphasizing the importance of energy balance in understanding the heat transfer process. The conversation highlights the necessity of grasping both the numerator and denominator of the equation for a complete understanding of heat transfer in reactor design.

PREREQUISITES
  • Understanding of heat transfer principles
  • Familiarity with fluid dynamics concepts
  • Knowledge of energy balance equations
  • Basic calculus for differential equations
NEXT STEPS
  • Study the derivation of the heat transfer equation in fluid flow
  • Learn about energy balance in thermal systems
  • Explore the implications of the heat transfer coefficient (h) in different fluids
  • Investigate the effects of varying tube diameters (D) on heat transfer rates
USEFUL FOR

Engineering students, thermal system designers, and professionals involved in reactor design and heat transfer analysis will benefit from this discussion.

MikeOngay
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Homework Statement



Not hw.. My teacher wants us to understand this as it is important for reactor design.

A liquid is flowing through a tube of diameter D. The inner wall of the tube is maintained at a constant temperature of Ts. The liquid enters at a temperature of Tw1and leaves at a temperature of Tw2. The heat transfer coefficient for the liquid under the conditions of flow is h. The length of the tube is L. Assume steady state. Show that the rate at which heat is transferred from the wall to the flowing liquid is given by
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Homework Equations


q=h (π D L)((Ts−Tw1)−(Ts−Tw2))/ln((TS−Tw1)(TS−Tw2))

The Attempt at a Solution


I am trying to understand why the above equation is right, the only thing I can't seem to get is the ln of the bottom term, I understand the numerator, or atleast I think I do.
 
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If you don't understand the denominator then you don't understand the numerator.

The starting equation for this derivation is:
WC_p(T(x+\Delta x)-T(x))=\pi D \Delta x h(T_s-T(x))
where W is the mass rate of flow and Cp is the heat capacity. Do you understand where this equation comes from?
Divide both sides of the equation by delta x, and take the limit as delta x approaches zero. What differential equation do you get?

Chet
 
This is embarrassing but I realized that I wasn't using an energy balance while trying to solve for the heats...

Thank you!
 

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