Condition for Equal Magnitudes of Projection Vectors?

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Homework Statement


The angle between two vectors a and b is ∅, where ∅≠90°. Under what conditions will |Projab|2 + |Projba|2 = 1?


Homework Equations


|Pab|= |[itex]\vec{a}[/itex][itex]\bullet[/itex][itex]\vec{b}[/itex]|/|[itex]\vec{b}[/itex]|

|Pba|= |[itex]\vec{a}[/itex][itex]\bullet[/itex][itex]\vec{b}[/itex]|/|[itex]\vec{a}[/itex]|


The Attempt at a Solution


I know that |Pab|=|Pba| when |[itex]\vec{a}[/itex]|=|[itex]\vec{b}[/itex]|

I'm not sure where I go from there.

Any help is appreciated, thanks.
 
on Phys.org
anonymoususer said:

Homework Statement


The angle between two vectors a and b is ∅, where ∅≠90°. Under what conditions will |Projab|2 + |Projba|2 = 1?


Homework Equations


|Pab|= |[itex]\vec{a}[/itex][itex]\bullet[/itex][itex]\vec{b}[/itex]|/|[itex]\vec{b}[/itex]|

|Pba|= |[itex]\vec{a}[/itex][itex]\bullet[/itex][itex]\vec{b}[/itex]|/|[itex]\vec{a}[/itex]|


The Attempt at a Solution


I know that |Pab|=|Pba| when |[itex]\vec{a}[/itex]|=|[itex]\vec{b}[/itex]|

I'm not sure where I go from there.

Any help is appreciated, thanks.

Looks to me like they just want you to derive an express for cos(∅) in terms of |a| and |b|.
 
Dick said:
Looks to me like they just want you to derive an express for cos(∅) in terms of |a| and |b|.

I think it's a little more complex than that. I am a little confused on what the question is asking though.
 
anonymoususer said:
I think it's a little more complex than that. I am a little confused on what the question is asking though.

I worked through it and that's the only thing I can figure they could be asking.
 

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