- #1

manish13

- 2

- 0

E[y-x|y>x]

I keep getting it negative, which is clearly wrong. Anybody wants to try it?

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- Thread starter manish13
- Start date

- #1

manish13

- 2

- 0

E[y-x|y>x]

I keep getting it negative, which is clearly wrong. Anybody wants to try it?

- #2

mathman

Science Advisor

- 8,066

- 543

Show your calculation. It should be easy to find the flaw.

- #3

manish13

- 2

- 0

[tex]E[t_2-t_1|t_2>t_1] = E[(t_2-t_1)*I_{\{t_2>t_1\}}] = \int_0^{\infty} \int_{t_1}^{\infty}(t_2-t_1)\lambda_1 \lambda_2 e^{-\lambda_1 t_1} e^{-\lambda_2 t_2} dt_2 dt_1[/tex]

This nicely gives the answer as [tex]\frac{\lambda_1}{\lambda_2(\lambda_1+\lambda_2)}[/tex]

I was doing a mistake in byparts.

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