Conditional Independence and Independence question

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SUMMARY

The discussion centers on the concepts of conditional independence and independence in probability theory. Specifically, it addresses whether \(T\) being independent of \(C\) given \(Z\) implies that \(T\) is independent of \(C\) without conditioning on \(Z\), and vice versa. The consensus is that neither implication holds true, as demonstrated by the definitions of independence and conditional independence. The mathematical representation \(P(T \wedge C|Z) = P(T|Z)P(C|Z)\) is crucial in understanding these relationships.

PREREQUISITES
  • Understanding of probability theory, particularly independence and conditional independence.
  • Familiarity with the notation and concepts of random variables \(T\), \(C\), and \(Z\).
  • Knowledge of probability distributions and their properties.
  • Basic skills in mathematical reasoning and proof techniques.
NEXT STEPS
  • Study the definitions of independence and conditional independence in probability theory.
  • Explore examples of conditional independence in Bayesian networks.
  • Learn about the implications of independence in statistical inference.
  • Investigate the role of conditioning in probability and its effects on independence.
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Students and professionals in statistics, data science, and machine learning who need a deeper understanding of independence concepts in probability theory.

akolman
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Hello, I am stuck with the following question.

1. Suppose T ind. C |Z, does it follow that T ind. C ?

2. Suppose T ind. C , does it follow that T ind. C |Z?

I think both don't follow, but I don't know how to show it

Thanks in advance
 
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akolman said:
Hello, I am stuck with the following question.

1. Suppose T ind. C |Z, does it follow that T ind. C ?

2. Suppose T ind. C , does it follow that T ind. C |Z?

I think both don't follow, but I don't know how to show it

Thanks in advance

\(T\) and \(C\) independent given \(Z\) means:

\(P(T \wedge C|Z)=P(T|Z)P(C|Z)\)

Now we are free to define any relation we want between \(T\) and \(C\) if \(\neg Z\) is the case so that

\(P(T \wedge C) \ne P(T)P(C)\)

CB
 
Last edited:

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