Conditions for a density matrix; constructing a density matrix

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Homework Help Overview

The discussion revolves around the conditions necessary for a matrix to represent the density operator of a pure state in quantum mechanics. Participants explore the properties of density matrices, particularly focusing on the trace and Hermitian nature of the matrix.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the requirement that the trace of the density matrix must equal one and question how to construct the density matrix itself. There are attempts to express relationships among the matrix elements based on the conditions provided, such as the implications of Hermiticity and the trace condition.

Discussion Status

The conversation is ongoing, with participants sharing insights and references to external resources. Some have offered guidance on using the trace and Hermitian properties to restrict the variables involved. There is a recognition that the problem may require finding a general form for the density matrix.

Contextual Notes

Participants note constraints regarding the choice of basis and the implications of the matrix being Hermitian. There are discussions about the implications of specific values for the matrix elements and how they relate to the conditions for a density matrix.

Juqon
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Homework Statement


What are the conditions so that the matrix [itex]\hat{p}[/itex] describes the density operator of a pure state?


Homework Equations


[PLAIN]http://img846.imageshack.us/img846/2835/densitymatrix.png
[itex]p=\sum p_{j}|\psi_{j}><\psi_{j}[/itex]

The Attempt at a Solution


I know that tr([itex]\rho[/itex])=1 for pure states.
But I do not know how to construct the density matrix. Or is it [itex]\hat{p}[/itex] already?
In my book, there is the example "hermitian, tr=1, [PLAIN]http://img89.imageshack.us/img89/4346/densitymatrixexample.png", but I do not know how they constructed that.

Maybe I can just say a+d+e=1; c,b arbitrary?
 
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What do you think about that?

[PLAIN]http://img155.imageshack.us/img155/7663/densitymatrixexamplep2.png
a²+bc=a (a[itex]\neq[/itex]0) => [itex]a+\frac{bc}{a}=1[/itex]
ab+bd=b (b[itex]\neq[/itex]0) => a+d=1 <=> a= 1-d <=> d=1-a
ca+dc=c (c[itex]\neq[/itex]0) => a+d = 1
cb+d²=2 (d[itex]\neq[/itex]0) => [itex]d+\frac{cb}{d}=1[/itex]
e=e²

a=0 v a= 1 - d
b € |R
c € |R
d=0 v d= 1 - a
e=0 v 1
 
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Ok, thanks, I have read that.

with the condition for the trace:
a+d+e=1 => e=0: a+d=1;
e=1: a=d=0

and since the matrix is hermitian and p^T=p:
b = c, c € |R

On the page you linked to it says only one element on the diagonale can be different from zero when you chose the right basis, but I think I can not change the basis here. So I think I can not further restrict it from that.
Right?
 
Juqon said:
Ok, thanks, I have read that.

with the condition for the trace:
a+d+e=1 => e=0: a+d=1;
e=1: a=d=0
For e=1, you can say a+d=0, which isn't quite the same as saying a=d=0.
and since the matrix is hermitian and p^T=p:
b = c, c € |R
Both b and c can be complex. At best you can say c=b*.
On the page you linked to it says only one element on the diagonale can be different from zero when you chose the right basis, but I think I can not change the basis here. So I think I can not further restrict it from that.
Right?
Yes, I agree. I think the problem wants you to find a general form for the density matrix.
 

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