Conducting Spheres and Their Charge

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SUMMARY

The discussion centers on the behavior of three identical conducting spheres, where one sphere initially carries a charge Q. When the spheres are brought into contact and then separated, the charge redistributes among them. The correct conclusion is that one sphere retains a charge of Q/2 while the other two spheres remain uncharged. This outcome is confirmed through the understanding of charge distribution in conductors.

PREREQUISITES
  • Understanding of electrostatics and charge distribution
  • Familiarity with conducting materials and their properties
  • Knowledge of basic physics concepts related to electric charge
  • Ability to analyze problems involving multiple conductors
NEXT STEPS
  • Study the principles of electrostatics in detail
  • Learn about charge distribution in conductors
  • Explore the concept of grounding and its effects on charged objects
  • Investigate the behavior of electric fields around conductors
USEFUL FOR

Students of physics, educators teaching electrostatics, and anyone interested in understanding the principles of charge distribution in conducting materials.

Nathew

Homework Statement


Suppose we have three identical conducting spheres and one of them carries a charge of Q. if they are lined up in a row and then separated one at a time without grounding them...
a. only one will be charged with Q
b. they will all be discharged
c. one of them will have a charge of Q/2
d. they will each have a charge of Q/3
e. none of these

Homework Equations





The Attempt at a Solution


my guess was d, but i don't really understand and grasp the question/concept. The answer is C. If someone could guide me in the right direction that would be great.
 
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Wait, I believe i got it. So when the 3 balls are together the charge Q spreads out as much as possible making the balls on either end Q/2 and the middle conductor with no charge. When one of the end balls is removed it keeps the charge of Q/2 and the process happens again with the other two balls. Is this right?
 
Yes.
 

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