# Understanding the Interaction Between a Charged Rod and a Metal Sphere

• JNOD
In summary, the sphere remains motionless because the electrostatic forces between the charged rod and the sphere cancel each other out. This is due to the redistribution of charges on the sphere, with more "like" charges being pushed away from the rod and "opposite" charges being pulled closer to the rod. This results in a balance of attraction and repulsion forces, keeping the sphere in a stationary position.
JNOD
Homework Statement
A thin, light, spherical metal shell is suspended from a thread. The sphere hangs straight down when a charged rod is held at 3 cm to the left of the metal sphere. It can be concluded that:

A. the charge of the sphere is the opposite sign of the charge of the rod.
B. the charge of the sphere is the same sign as the charge of the rod.
C. the sphere is charged, but the sign of the charge is unknown.
D. the sphere is uncharged.

Relevant Equations
None
(A) incorrect, because opposite signs attract, and the sphere would've been drawn to the charged rod.
(B) correct, according to the answer key, but if the charge of the sphere and the charge of the rod are the same, then wouldn't they repel each other? I'm confused as to why this is the correct choice.
(C) incorrect, because if the sphere is charged, it will either move away or toward the charged rod, but it "hangs straight down" instead.
(D) incorrect, because even if the sphere is uncharged, the presence of a charged rod would induced a charge on the sphere.

Honestly I am baffled by this question. I'm not sure if there's something I'm not understanding. This is not conductive charging since no contact was implied. I'm assuming it has something to do with induction and polarization. Any hints or help is appreciated.

Delta2
There are two effects at work here. First there is the force between the rod and the sphere due to the total charges on each. Then there is the force between the rod and the sphere due to the change in the charge distribution on the sphere that is induced by the charge of the rod. What do you know about both of these effects?

JNOD
JNOD said:
(C) incorrect, because if the sphere is charged, it will either move away or toward the charged rod, but it "hangs straight down" instead.
(D) incorrect, because even if the sphere is uncharged, the presence of a charged rod would induced a charge on the sphere.
@Orodruin has already given you the hint, but note the implication of your two correct statements above. With no charge they would attract, and with a sufficient like charge they would repel. So in between...

JNOD
Orodruin said:
There are two effects at work here. First there is the force between the rod and the sphere due to the total charges on each. Then there is the force between the rod and the sphere due to the change in the charge distribution on the sphere that is induced by the charge of the rod. What do you know about both of these effects?
The force between the charges of the rod and the sphere due to the total charges on each is determined by Coulomb's law? We know that the sphere is a conductive object, which can stay electrostatically neutral in the presence of a charged rod, since it is able to become polarized.

The force between the rod and the sphere due to change in the charge distribution on the sphere after induction by rod is also determined by Coulomb's law? Can we assume that the "opposite" charges on the sphere have moved closer to the charged rod and "like" charges on the sphere have moved farther away, to the extent that the force of repulsion is equal to the force of attraction, which explains why there is no movement horizontally? Since the "opposite" charges on the sphere is closer to the charged rod, the force of attraction is greater; however since there is no net movement, we can assume that there are more "same" charges on the metal sphere to repel the rod, since it is at a greater distance from the rod?

haruspex said:
@Orodruin has already given you the hint, but note the implication of your two correct statements above. With no charge they would attract, and with a sufficient like charge they would repel. So in between...
I guess I was tripped up by the wording of the question. It's asking for the sign of the charge, not the magnitude. In my head, I thought that there was no scenario in which the sphere was motionless, since same signs attract, opposite signs repel, and uncharged sphere + charged rod will result in an attraction.

In order for the sphere to remain motionless, the electrostatic forces have to be such in that they cancel each other out, which means the sphere cannot be neutral. It has to possesses more "like" charges in order to repel the attractive forces between the charged rod and the "opposite" charges that have redistributed closer to the rod.

Delta2
JNOD said:
I guess I was tripped up by the wording of the question. It's asking for the sign of the charge, not the magnitude. In my head, I thought that there was no scenario in which the sphere was motionless, since same signs attract, opposite signs repel, and uncharged sphere + charged rod will result in an attraction.

In order for the sphere to remain motionless, the electrostatic forces have to be such in that they cancel each other out, which means the sphere cannot be neutral. It has to possesses more "like" charges in order to repel the attractive forces between the charged rod and the "opposite" charges that have redistributed closer to the rod.
Yes.

Delta2
haruspex said:
Yes.
Thank you!

## 1. What is the purpose of the metal sphere and charged rod experiment?

The purpose of this experiment is to demonstrate the principles of electrostatics and how charges interact with each other.

## 2. How does the metal sphere become charged?

The metal sphere becomes charged when it is brought into contact with the charged rod. The charge from the rod is transferred onto the sphere, causing it to become charged as well.

## 3. What happens when the charged rod is brought near the metal sphere?

When the charged rod is brought near the metal sphere, the sphere will experience a force due to the electric field created by the charged rod. If the rod has a positive charge, the sphere will be repelled. If the rod has a negative charge, the sphere will be attracted.

## 4. Can the charge on the metal sphere be changed?

Yes, the charge on the metal sphere can be changed by bringing it into contact with a different charged object. If the sphere is brought into contact with a positively charged object, it will acquire a positive charge. If it is brought into contact with a negatively charged object, it will acquire a negative charge.

## 5. What is the significance of using a metal sphere in this experiment?

A metal sphere is used in this experiment because it allows the charge to distribute evenly over its surface. This ensures that the electric field is uniform and the resulting forces can be accurately measured and observed.

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