Describing Biholomorphic Self Maps of Punctured Plane

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SUMMARY

The discussion focuses on describing biholomorphic self-maps of the multiply punctured plane, specifically the complex plane C with n points removed, denoted as C\{p1, p2, p3, ..., pn}. The participants emphasize the need to map the Riemann sphere to itself using the transformation (az+b)/(cz+d) while permuting the points {p1, ..., pn, ∞}. The conclusion drawn is that the automorphism group for this mapping is the full symmetric group on n letters, confirming the complexity of conformal self-maps in this context.

PREREQUISITES
  • Understanding of biholomorphic mappings
  • Familiarity with Riemann surfaces
  • Knowledge of the transformation (az+b)/(cz+d)
  • Concept of symmetric groups in mathematics
NEXT STEPS
  • Study the properties of Riemann surfaces and their mappings
  • Explore the full symmetric group and its applications in complex analysis
  • Research conformal mappings in the context of punctured planes
  • Investigate the implications of removable singularities in complex functions
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Mathematicians, particularly those specializing in complex analysis, algebraic geometry, and anyone studying the properties of biholomorphic mappings and Riemann surfaces.

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how do we describe the biholomorphic self maps of the multiply puncture plane onto itself?
I mean C\{pi,p2,p3..pn}

Plane with n points taken away.

I wanted to generailze the result for the conformal self maps of the punctured plane, but I do feel these are quite different animals.
I thank you for any help/suggestions
 
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The singularities (and infinity) are removable. So you need to map the sphere to itself (az+b)/(cz+d) in such a way that you permute the points \{p_1,\dots,p_n,\infty\}.
 
Last edited:
I thank you edgar,

I think I see it now. So I suspect we get the full symmetric group on n letters then, as the automorphism group. Thank you again
 

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