Confused by Operator Algebra: Checking Intermediate Step

  • Context: Graduate 
  • Thread starter Thread starter BWV
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SUMMARY

The discussion centers on the operator algebra related to the commutator of position (q) and momentum (p) operators in quantum mechanics. The user confirms the correctness of their intermediate step in the differentiation process, which involves applying the product rule. The intermediate step derived is d/dx (x Ψ(x)) = d/dx x Ψ(x) + x d/dx Ψ(x) - x d/dx Ψ(x), simplifying to d/dx x = 1. The participants agree on the validity of this calculation.

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically operator algebra.
  • Familiarity with the product rule in calculus.
  • Knowledge of wave functions and their derivatives in quantum mechanics.
  • Basic comprehension of commutation relations between operators.
NEXT STEPS
  • Study the derivation of the commutation relation [q, p] = iħ.
  • Learn about the implications of operator algebra in quantum mechanics.
  • Explore advanced applications of the product rule in quantum mechanics problems.
  • Investigate the role of wave functions in quantum mechanics and their mathematical treatment.
USEFUL FOR

Students and professionals in physics, particularly those focusing on quantum mechanics, as well as educators teaching operator algebra concepts.

BWV
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I get confused by the operator algebra - this is the commutator for q & p from wikipedia
Am I correct on the intermediate step I plugged in there?

296ebfb900298b88e8f5ba9f793dc93c.png


because of the product rule you get as the intermediate step:

=d/dx x Ψ(x) + x d/dx Ψ(x) - x d/dx Ψ(x)

and d/dx x =1

so

edd53c9f1001e42bb424104f7c283eda.png
 
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Looks good.
 
Great, thanks for looking at it
 

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