Here is the diagram and work the answer booklet says: http://img69.imageshack.us/img69/2593/untitled1copy7wg.jpg [Broken] Okay first question, If you loook on the image and look at the Current Source Is, the arrow shows its going up and to the left, so that means its going to go through the 2.5 OHM resistor, but you can see the picture its labeled +^v^v - so that means its going to not have a voltage drop but an increase and isn't the rule it should always decrease with the flow of current? all the other resistors follow this rule in the diagram. Okay now to the real problem: I'm confused on how they found i2, which i'm assuming is the current flowing into Resistor with 2 OHMS, with voltage of v2. They say: v2 = v1.5/1.5 OHM - v14/15OHM = 6v/1.5 ohm - 14v/14 ohm = 3A Why are they only using v1.5 and v14 to find this? if u used KVL, wouldn't u sum up the middle loop and get: start at V2 going clock wise, -V2 - V4 + V14 = 0; so V2 = -V4 + V14 but they arn't even using V4 instead they are using V1.5, but why? Thanks !