Voltage drop and current through each resistor

[SacredBlood]

Homework Statement

Determine the voltage drop and current through each resistor.

*This is just my sketch of the problem since I couldn't take a clear picture of it.

Homework Equations

Ohm's law
V= IR

Parallel total resistance
R_eq=1/R1+1/R2+1/R3+...

Series total resistance
R_eq=R1+R2+R3+...

The Attempt at a Solution

I'm having troubles understand what I should do when there's more than just a parallel or series in a circuit.

If this were just a parallel problem then I would simply add up the resistors using the R_eq=1/R1+1/R2+1/R3+... equation and since I know that voltage is the same across a parallel circuit then I could simply solve for the total current (Ieq) by rearranging Ohm's law I_eq=V/R_eq from there I can figure out voltage drop and current through every resistor using V1=I_eqR1, V2=I_eqR2,... and I1=V/R1, I2=V/R2,...

I would follow the same steps in a series circuit problem with the exception being that I would use R_eq=R1+R2+R3... instead of R_eq=1/R1+1/R2+1/R3+...

Now, with my problem, I have both parallel and series. How should I go about doing this?

I tried simplifying the circuit down and got an R_eq=14.6 ohms with the Voltage still being 10 volts. In this case would I use this R_eq value to calculate I_eq and just use that for the voltage drop and then just divide voltage by every resistor to figure out the current through each?

Maybe I don't understand circuits correctly. I'm not sure. Any help/explanation is very much appreciated!

 

[andrevdh]

With the equivalent resistance you can calculate the current through the 6 ohm resistor and the parallel combination (the current would split up through the two branches of the parallel combination though).
That means you can calculate the voltage over the 6 ohm resistor and the total voltage over the two parallel branches.

 

[TomHart]

Welcome to Physics Forums.

A suggestion: When posting figures, you should use sufficient resolution so that the figure easily conveys all of the information. The values in your figure are simply not legible. For example, I would not have guessed the DC voltage to be 10 V - as you stated.

 

[phinds]

The values in your figure are simply not legible.

+1 on that

For example, I would not have guessed the DC voltage to be 10 V - as you stated.

Neither would I since it clearly says 20v in the figure