Confused with working out the span of a set of vectors in R^2

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SUMMARY

The discussion centers on the span of the set S, defined as all vectors x=(x₁, x₂) in ℝ² where x₁=1. The conclusion is that span S equals ℝ², as any vector in ℝ² can be expressed as a linear combination of vectors in S. The confusion arises from the conditions where x₁ is both equal to 1 and 0, which are clarified as separate cases to demonstrate that all points in ℝ² can be represented using linear combinations of vectors from S.

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  • Basic knowledge of the real number system ℝ
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  • Explore the properties of vector spaces in ℝ²
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Students and educators in mathematics, particularly those focusing on linear algebra, as well as anyone seeking to deepen their understanding of vector spaces and spans in ℝ².

gilabert1985
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Hi everyone!

I have the following problem which I don't understand... It is already solved, but there are three questions I have regarding it.

The problem says: "Let S be the set of all vectors x=(x_{1}, x_{2}) in \Re^{2} such that x_{1}=1. What is the span of S?"

And here is the answer that has me so confused...

"span S = \Re^{2} because (x_{1}, x_{2})=x_{1}(1, x^{-1}_{1}x_{2} when x_{1}\neq0
and (x_{1}, x_{2})=(1, 0)-(1, -x_{2}) when x_{1}=0."

But I don't understand the first line... why does it say when x_{1}\neq0 if x_{1} is supposed to be equal to 1?

And in the second line, the same... why is x_{1}=0?

So yeah, I understand they are linear combinations and all that, but for the condition given (x_{1}=1), I don't understand how this answer satisfies it.
 
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The points (x1,x2) in the lines that are confusing you are not points in S, but points in R2, which it then shows how to represent as linear combinations of points in S
 
Since you can't rewrite ##x_2## as ##x_1 x_1{}^{-1}x_2## when ##x_1=0##, you have to consider the case ##x_1=0## separately.
 

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