Confusion About Simple AM Radio Receiver/Tuner

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The discussion centers on the confusion surrounding the design of an AM radio receiver circuit, specifically the role of inductors and capacitors in frequency resonance. Participants clarify that the inductor and capacitors work together to create a resonant circuit, which can act as a band-pass filter, allowing specific frequencies to be processed. The transformer is noted as crucial for tuning the circuit to resonate at a desired frequency, enhancing the voltage from the antenna signal. After rectification by the diode, a low-pass filter formed by a resistor and capacitor removes high-frequency components, leaving audio signals for amplification. Understanding these components and their interactions is essential for grasping the circuit's functionality.
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I am confused by the design of this AM receiver/tuner circuit.

http://imgur.com/f9n05

I don't understand how the inductor and capacitors on the left design a circuit that resonates at a certain frequency, and I also don't understand why the resistor and capacitor in parallel after the diode create a low-pass filter.

Are the inductor and two capacitors not in parallel with each other? This circuit makes more sense to me if I consider the two capacitors to be in parallel with each other, and in series with the inductor. Then the inductor and capacitors should exhibit resonance at a given frequency and act as a band-pass filter, passing this specific frequency to the rest of the circuit. Is this right?

Can anyone help me out with this circuit?
 
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In this circuit it doesn't matter if you consider the two capacitors in parallel are in series or in parallel with the inductor, the effect is the same.

Imagine the inductor as a mass that is being moved at a regular frequency by the antenna. The capacitors are like a spring that is alternately compressed and stretched by the oscillating mass. Since the spring keeps the mass oscillating, the antenna only has to supply enough input power to offset the losses due to friction. The oscillation of the mass will increase until the losses equal the power input from the antenna.

Likewise in the circuit, the voltage in the inductor-capacitor circuit increases until the losses equal the power supplied by the antenna. If the voltage is high enough, the positive peaks of the oscillation will pass through the diode and charge the capacitor. The 10K resistor allows the capacitor to discharge when the peak of the signal is less than the voltage the capacitor is charged to. In this way the voltage across the final capacitor follows the peak voltage of the signal. When amplified it provides an audio output.
 
Glenn900 said:
I am confused by the design of this AM receiver/tuner circuit.

http://imgur.com/f9n05

I don't understand how the inductor and capacitors on the left design a circuit that resonates at a certain frequency, and I also don't understand why the resistor and capacitor in parallel after the diode create a low-pass filter.

Are the inductor and two capacitors not in parallel with each other? This circuit makes more sense to me if I consider the two capacitors to be in parallel with each other, and in series with the inductor. Then the inductor and capacitors should exhibit resonance at a given frequency and act as a band-pass filter, passing this specific frequency to the rest of the circuit. Is this right?

Can anyone help me out with this circuit?

There is a transformer at the left. This carries a signal from the antenna in the primary and the secondary is tuned with the capacitors so that it resonates with them at one frequency.

At this frequency, there is a step-up in voltage and this voltage appears across the secondary of the transformer.

This voltage is then rectified by the detector diode and the resulting waveform is filtered to remove the high frequency components, leaving only audio. This is amplified in the amplified speaker.

The capacitor C is variable and allows tuning of the parallel tuned circuit to receive different frequencies.
 
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