Confusion - Diff Eq for a Circuit? What does my professor mean?

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SUMMARY

The discussion centers on deriving a differential equation for the current in a series circuit containing a battery with voltage E, a resistor with resistance R, and an inductor with inductance L. The user initially misinterprets the notation "iR" as the resistance instead of the correct representation of current. After setting up the differential equation i(t)*R + L(d/dt)i(t) = 0, they integrate to find i(t) = Cexp(-(R/L)t). However, confusion arises when solving for initial conditions, specifically i(0) = 0, leading to the conclusion that C must equal 0, resulting in no current flow. The user ultimately clarifies the correct form of the equation as E = i(t)R + Ldi/dt.

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Homework Statement



My professor wants us to derive a differential equation for the current in a circuit.

The circuit has a battery with voltage E, resistor with resistance (iR)??, and inductance L. It's in series.


The Attempt at a Solution



What REALLY confuses me are these things:

Why iR instead of R? Is the i supposed to represent current? Then why is it given for the resistance and not inductance? I don't think it could be a complex number.. it just wouldn't make sense.

Anyway, I assumed she meant R instead of iR. Then I set up a diff eq like this:

i(t)*R + L(d/dt)i(t) = 0
after a bit of math, I got
d(i(t))/i(t) = -(R/L)dt
and integrating some more math...
i(t) = Cexp(-(R/L)t) where C is some constant.
okay, that's fine. It seems to make sense to me

But then she wants us to solve it if i(0) = 0 and i(t=0) = 0.

First of all.. isn't she saying the exact same thing twice? i(0) = i(t=0) I'm guessing?
And second of all... according to my equation, i(0) = Cexp(0) = 0 implies C = 0, or that the whole expression is 0. How do I solve the differential equation if C = 0 exactly? Or does it only have a solution of 0?

Any clarification could help. Thanks!
 
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Shouldn't it be

E = i(t)R+ Ldi/dt
 
ah, okay. that makes more sense. I should be able to figure something out - thanks!
 

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