Undergrad Did I Make a Mistake in my Coordinates? Help Needed!

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The discussion revolves around the correct coordinates of point B, initially questioned as either (a cos theta, a sin theta) or (-a cos theta, a sin theta). Participants clarify that the labeling in the diagram is accurate, noting that cos theta is negative in the second and third quadrants. The confusion arises from treating the x-coordinate as a positive length without considering its position relative to the origin. Ultimately, the correct interpretation confirms that the x-coordinate should indeed be negative based on the defined origin. The clarification resolves the initial misunderstanding.
Shafia Zahin
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In the attached pic,it is shown that the coordinates of point B are (a cos theta, a sin theta) ,but shouldn't it be (-a cos theta,a sin theta)? Can anybody please help?
 

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No there is nothing wrong with the labeling of the coordinates in the diagram. Recall that ##\cos \theta## is negative for ##\pi/2 < \theta < 3\pi/2## (or what you may know as the second and third quadrants).
 
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Fightfish said:
No there is nothing wrong with the labeling of the coordinates in the diagram. Recall that ##\cos \theta## is negative for ##\pi/2 < \theta < 3\pi/2## (or what you may know as the second and third quadrants).
But didn't it come like this?(see the attachment)
 

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When you did the triangle construction in your diagram, you treated ##x## there as a length, which only takes on positive values, but ignored its position relative to where the origin was defined. So, the x-coordinate of the point should in fact be the negative of the ##x## in your derivation.
 
Fightfish said:
When you did the triangle construction in your diagram, you treated ##x## there as a length, which only takes on positive values, but ignored its position relative to where the origin was defined. So, the x-coordinate of the point should in fact be the negative of the ##x## in your derivation.
Oh,now I got it,thank you so much:smile:
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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