Confusion of circle and sphere for physics problems

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The discussion revolves around the confusion between using the surface area of a sphere and a circle for solving physics problems related to pressure and force. The original attempt incorrectly applied the formula for the surface area of a sphere, leading to an erroneous calculation of force. A friend suggested using the area of a circle instead, which yielded the correct answer. The key clarification is that pressure acts perpendicularly to the surface, and when dealing with a hemisphere, the effective area is the projected area rather than the full surface area. Understanding this distinction is crucial for accurately resolving forces in physics problems involving pressure.
zabachi
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Homework Statement



The problem is attached

Homework Equations



P=F/A

The Attempt at a Solution



I did the question like this (got wrong answer though):

Surface area of sphere=4∏r2=4×∏×0.252
Atmospheric pressure=1.01×105

Force=1.01×105×4×∏×0.252≈80000N
Actual answer 20000N

So my friend said something about using a circle instead? I tried it and indeed got the right answer. So why do we use a circle's area instead of sphere.
 

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Check the value of radius.
 
i Changed the radius but the answer still reamins the same as i did the question previously itself
 
Pressure is the force per unit area applied in a direction perpendicular to the surface of an object.

The force is not completely perpendicular to the whole surface of hemisphere.
 
You have to resolve the pressure force acting on each element of area of one of the hemispheres into the component in the direction that the rope is pulling. This is equivalent to using the projected area of the hemisphere times the atmospheric pressure.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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