Confusion over acceleration of gravity as positive/negative

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
10 replies · 2K views
helloworld2941
Messages
6
Reaction score
2
Homework Statement
A skateboarder jumps horizontally off the top of a stairs and lands at bottom of the stairs. The staircase has a horizontal length of 12m, and the jump lasts 1.10s. We can ignore air resistance.
Relevant Equations
V = u + at
skateboard.png


okay I annotated the diagram given and the grey thing where they take y axis up as positive is what I understand to be, right?

But in the answers, they start off by going V = u - gt. They've taken acceleration due to gravity as a negative value. Why? I thought the skateboarder was falling downwards, and gravity acts downwards, so shouldn't it be positive?

Because I have understood that in other questions where upwards is positive and it'll ask something like a ball is projected upwards, that's when gravity is negative? Or did I confuse the the sign conventions and in those questions they actually took downwards as positive?

I am so confused. The answer is 10.78ms^-1 down which I would get the magnitude but have messed up the sign because my first instinct was to have acceleration due to gravity as positive, V = u + gt before subbing values.

Thank you so much
 
on Phys.org
The diagram indicates that upward displacements are positive. To avoid confusion, it helps then to make upward velocities and accelerations positive.
By convention "g" is a magnitude, so positive.
Since gravitational acceleration is downwards, and we are taking upward acceleration as positive, the acceleration due to gravity must be negative, so -g.
v=u+at=u-gt.
 
Reply
  • Like
Likes   Reactions: helloworld2941 and PeroK
haruspex said:
The diagram indicates that upward displacements are positive. To avoid confusion, it helps then to make upward velocities and accelerations positive.
By convention "g" is a magnitude, so positive.
Since gravitational acceleration is downwards, and we are taking upward acceleration as positive, the acceleration due to gravity must be negative, so -g.
v=u+at=u-gt.
Thank you, I understand it for this question now. But then in scenarios where a ball is projected upwards, would the acceleration due to gravity be positive or negative?
 
helloworld2941 said:
Thank you, I understand it for this question now. But then in scenarios where a ball is projected upwards, would the acceleration due to gravity be positive or negative?
If you throw a ball upwards and the acceleration due to gravity is positive, then the ball will accelerate starting at the initial velocity and just go on up forever.
 
Reply
  • Like
Likes   Reactions: Lnewqban and helloworld2941
helloworld2941 said:
Thank you, I understand it for this question now. But then in scenarios where a ball is projected upwards, would the acceleration due to gravity be positive or negative?
Necessarily falling is in the direction of gravity. You can choose whether to represent that direction as positive or negative.
It doesn’t matter which way the ball starts moving. If it starts upwards then that velocity and gravity will have opposite signs. Consequently the magnitude of the velocity decreases at first, as you would expect.
 
Reply
  • Like
Likes   Reactions: helloworld2941
phinds said:
If you throw a ball upwards and the acceleration due to gravity is positive, then the ball will accelerate starting at the initial velocity and just go on up forever.
Wait that's such a good way of thinking about. I've never learnt of it like that
 
Reply
  • Like
Likes   Reactions: phinds
helloworld2941 said:
Thank you, I understand it for this question now. But then in scenarios where a ball is projected upwards, would the acceleration due to gravity be positive or negative?
It's up to you, as part of setting up the solution to a problem, to decide which direction is positive. Unless the problem statement already includes this decision.

Suppose a car is moving along the road from left to right. To someone facing you on the the opposite side of the road the car is moving from right to left. If you both use the convention that the positive x-axis goes from left to right, then you would naturally give the car a positive velocity and the other observer would give the car a negative velocity. Both represent the same physical scenario.
 
Reply
  • Like
Likes   Reactions: jbriggs444
helloworld2941 said:
Thank you, I understand it for this question now. But then in scenarios where a ball is projected upwards, would the acceleration due to gravity be positive or negative?
This is important: The reason you are being assigned these questions is much more than just doing the calculations by rote; what you are learning is to understand and interpret what the question is asking, and how to correctly determine such things as variables and signs.
 
Reply
  • Like
Likes   Reactions: SammyS, Lnewqban and phinds
DaveC426913 said:
This is important: The reason you are being assigned these questions is much more than just doing the calculations by rote; what you are learning is to understand and interpret what the question is asking, and how to correctly determine such things as variables and signs.
what he said (small).jpg


Which is why, post #4
 
phinds said:
Which is why, post #4
Yes. I felt it was worth repeating. In principle, such understanding is a more important lesson than doing the math.