Confusion with Disconnected sets

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SUMMARY

The discussion centers on the connectedness of the set X = (0,1] ∪ (1,2) under the usual metric topology of the reals. The user is confused about how this set can be connected, given the definition of disconnectedness involving open sets G and V. The key conclusion is that the set (0,1] ∪ (1,2) is indeed connected because it can be represented as the interval (0,2), which is a single connected component. The user is reminded that (0,1] is not an open set, which is crucial for applying the definition correctly.

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Mr-T
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Hello,

I am having some difficulties understanding why a subset under the usual metric topology of the reals is connected.

How can a set X = (0,1] u (1,2) be connected?

The definition I am using is:

A is disconnected if there exists two open sets G and V and the following three properties hold:

(1) A intersect G ≠ ∅
A intersect V ≠ ∅

(2) A is a proper subset of the union of G and V.

(3) the intersection of G and V is the empty set.

Thanks
 
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And you also want ##G## and ##V## to be open. No?
 
Yea, that would be more correct.
 
Okay, so can you find two such open sets for (0, 1]\cup (1, 2)? (0, 1] and (1, 2) will not do because (0, 1] is not open. (And, did you notice that (0, 1]\cup (1, 2)= (0, 2)?)
 

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