Conics Problem Part 2: Formulas and Solutions | Homework Statement

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SUMMARY

This discussion focuses on solving a conics problem related to hyperbolas, specifically addressing the calculation of the variable 'b' using the formula b² = c² - a². The values provided are a = 10 and c = 30, leading to the correct determination of b as 10. The user also clarifies the need to use the correct form of the hyperbola equation, which is \(\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\), emphasizing the importance of identifying the correct parameters in hyperbola equations.

PREREQUISITES
  • Understanding of hyperbola equations and their standard forms
  • Familiarity with the relationship between the variables a, b, and c in conic sections
  • Basic algebra skills for manipulating equations
  • Knowledge of coordinate geometry, particularly with respect to conics
NEXT STEPS
  • Study the derivation and applications of the hyperbola equation
  • Learn about the properties of conic sections, focusing on hyperbolas
  • Explore examples of hyperbola problems involving foci and vertices
  • Investigate the differences between horizontal and vertical hyperbola equations
USEFUL FOR

Students studying conic sections, mathematics educators, and anyone seeking to deepen their understanding of hyperbolas and their properties in coordinate geometry.

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Homework Statement


This is the second page.
http://img116.imageshack.us/img116/7519/arch2iq9.jpg​
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Homework Equations


Formulas on picture above.


The Attempt at a Solution


I'am just wondering if everything looks fine.
 
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part (i) is correct.
For part (ii), I don't think that's how you would solve for b. There's a formula to solve for b. b^2=c^2-a^2 where c is your focii and a is the distance from your center (0,30) to the vertex of the hyperbola. a=10, c=30, then b=?
 
Whoops, I realized that the problem is using a different form of the vertical hyperbola instead of \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1, so in this case I switched a and b around.

In this problem, where b=10(the distance from center to vertex of hyperbola) is correct.
 

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