Conics - Semi Major/Minor Axis

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SUMMARY

The discussion focuses on determining the semi-major and semi-minor axes of an ellipse defined by the equation 25x² + 350x + 9y² - 54y + 1081 = 0. The center of the ellipse is identified as [7, 3], with foci located at [11, 3] and [3, 3]. To find the lengths of the semi-major and semi-minor axes, the equation must be rewritten in the standard form \(\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\), where 'a' and 'b' represent the lengths of the axes.

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katrina007
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Hi,

I have this homework question and I completed and found the the foci and the center for the ellipse, but I don't understand how to find the semi major and minor axis.

Graph and give the center, semi major and semi minor axis and foci of the ellipse

25x^2 + 350x + 9y^2 - 54y +1081 = 0


For the center and Foci I got:
Center: [7, 3]
Foci: [11, 3] & [3, 3]

If anyone can help me with this, that'd be appreciated. Thanks in advance.
- Katrina
 
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The major axis is the line that joins the foci.
The minor axis is the line that goes through the center of the ellipse, and is perpendicular to the major axis.
 
i still don't know what the means or how to figure out the axis...can someone please tell me the axis and how they got it? do i need to use formula or something?
 
How did you find the center and foci? If you did the usual complete the squares routine then the axis lengths can be read off from that.
 
yes i did that...but what do i read to tell the major/minor axes?
 
So if you have it in the form
\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1
a and b are what you need to look at.
 

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