Connection between Tension/Torque/Inertia, & linear acceleration

[JournaL]

Homework Statement

A block with mass m = 5.00 kg slides down a surface inclined 36.9 degrees to the horizontal. The coefficient of kinetic friction is 0.25. A string attached to the block is wrapped around a flywheel on a fixed axis at O. The flywheel has mass 25.0 kg and moment of inertia 0.500 kg m^2 with respect to the axis of rotation. The string pulls without slipping at a perpendicular distance of 0.400 m from that axis.

Calculate the Acceleration of the block.
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Homework Equations

So far I drew up two Free Body Diagrams, one of the block and another of the Pulley.

Torque = Inertia * Angular Acceleration

Angular Acceleration= linear accelreation/ radius

Newton's 2nd Law

The Attempt at a Solution

So far I know that the pulley mass is not needed to find the acceleration of the block (according to my friend).

I used Newton's 2nd Law for the Tension of the block

Tension= mg( sin( theta) - Uk cos(theta ) - ma

Somehow I have to tie this with the Torque, but I don't know how. Would the levers be considered the radius?

Torque Net = Tension (r) - Uk (mg*r) , which would then equal to Inertia * linear acceleration/ Radius?

 

[JournaL]

I got the answer to be 1.744 m/s^2

Is this right?