Conservation of Angular Momentum in a Three Mass System

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Homework Help Overview

The problem involves a system of three masses connected by a rigid rod, rotating about the center of mass (CM) in a gravity-free environment. The scenario describes a collision between one of the rotating masses and a stationary mass, raising questions about the conservation of angular momentum before and after the collision.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of conservation laws, particularly focusing on linear and angular momentum. There are attempts to calculate the new center of mass and the moment of inertia after the collision, as well as questions about the implications of these changes on angular velocity.

Discussion Status

The discussion is ongoing, with participants exploring the implications of the collision on the system's angular momentum and the need to recalculate the moment of inertia. There is an acknowledgment of the need to carefully consider the new center of mass and its effect on the system's dynamics.

Contextual Notes

Participants note the importance of recalculating the moment of inertia after the collision and the potential changes in the center of mass position. There is a focus on ensuring that angular momentum is conserved throughout the process.

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Homework Statement



Two masses M each are connected by a rigid rod of negligible mass having length a.The CM of the system is stationary in a gravity free space and the system rotates about the CM. with angular velocity w.One of the rotating masses strikes a third stationary ball of mass M which sticks to it.What is the angular momentum of the three mass system before and after collision?

Homework Equations



The Attempt at a Solution



For the collision conservation of linear momentum will be applicable.
Mv=2Mv' or,v'=v/2=wa/4. From this w' can be calculated.

Prior collision,L=Iw where I is the MI of the two mass system.

After collision, L'=I'w'

Please check if I am correct.
 
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the system will rotate about new center of mass. Check for the position of new center of mass!
 
So,we are to be careful to calculate I for the second time.
Second time, CM will be a/3 rd distance away from the mass 2M.Accordingly,I will change.

But angular velocity would be same as w'.Right?
 
There will be no linear momentum...
angular momentum will be conserved...
CM will change the position...
And if one wants to find w',one has to find I' carefully.
 

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