Conservation of angular momentum in nuclear physics

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SUMMARY

The discussion centers on the conservation of angular momentum in nuclear decay, specifically involving a uranium-238 nucleus decaying into thorium-234 and an alpha particle. It is established that the total angular momentum of the resulting thorium-234 nucleus and alpha particle will equal the initial angular momentum of the uranium-238 nucleus, denoted as II. Additionally, if a photon is emitted during the decay, the equation Ithorium + Iα + ħ = II holds true, emphasizing the need to account for orbital angular momentum in these calculations.

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  • Understanding of angular momentum in nuclear physics
  • Familiarity with uranium-238 and thorium-234 isotopes
  • Knowledge of alpha decay processes
  • Basic principles of photon emission in nuclear reactions
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burgjeff
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Say a uranium-238 nucleus with angular momentum II decays to thorium-234 plus an alpha particle. Will the sum of the angular momenta of the thorium-234 nucleus and the alpha particle equal II? What if a photon was emitted during this process, would Ithorium+Iα+hbar=II?

thanks
 
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The relative motion of the nuclei can carry angular momentum, so the result can be different.
 
To clarify mfb's point, orbital angular momentum must be included when applying angular momentum conservation. But yes, angular momentum is definitely always conserved.
 

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