Conservation of Energy Challenge Problem

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SUMMARY

The discussion focuses on a physics problem involving a 2.0 kg cart with a spring (k=5000 N/m) colliding with a stationary 1.0 kg cart. The maximum compression of the spring during the collision is calculated to be 0.046 m, using conservation of momentum and energy principles. After the collision, the speed of the combined carts is determined to be 2.67 m/s, leveraging the elastic collision properties and conservation laws. The solution emphasizes the importance of applying both momentum and kinetic energy conservation for accurate results.

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  • Understanding of conservation of momentum
  • Familiarity with kinetic energy equations
  • Knowledge of elastic collision principles
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Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators seeking to enhance their teaching methods in collision dynamics.

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Homework Statement


A 2.0 kg cart has a sping with k= 5000 N/m attached to its front, parallel to the ground. This cart rolls at 4.0 m/s toward a stationary 1.0 kg cart.

a) What is the maximum compression of the spring during the collision?

b) What is the speed of each cart after the collision?


Homework Equations



KE=(1/2)mv^2 Us=(1/2)kx^2

The Attempt at a Solution



I got the first part:

Using first conservation of momentum and assuming the cars stick together momentarily
then using conservation of energy

(2kg)(4m/s)=(3kg)v1
v1= 2.67 m/s
(.5)(2kg)(4m/s)^2=(.5)(5000N/m)(x)^2 + (.5)(3kg)(2.67m/s)^2
x= .046 m

But I'm not sure what to do with the second part. Any suggestions?
 
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But I'm not sure what to do with the second part. Any suggestions?

That's the easiest part. Since this was a completely elastic collision, the elastic co-eff =1. So, final relative velocity = initial relative velocity. This, combined with the conservation of momentum, gives you two unknowns with two eqns.

Of course, you can also use conservation of total KE, but that's lengthier.

Good job in solving part A.
 

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