# Conservation of Energy Confusion

Question:
A person wants to jump in the air. To do so, he has to crouch a distance C. He then has a push-off phase, where the he accelerates upwards by a distance C. At the end of push-off, he then achieves takeoff (airborne). The end of his takeoff distance is H, and H is the difference between maximum jump height and end of crouch distance.

My professor says the Cons of E. equation is FC = mgH + WC, with this reasoning:

"The total energy you need to take off at the moment of the take-off = F (reaction force) X C (distance).
The total energy you spend during the push-off till the take off = potential energy to reach the jumping distance, H (mgH) + kinetic energy to overcome the gravity of the person (WC).
Therefore, FC = mgH + WC"

I don't quite understand his reasoning for this. Is there something more intuitive anyone can share?

anorlunda
Staff Emeritus
At the top of the leap, speed is zero, so there is zero kinetic energy.

Your gravitational potential energy at the top is higher than at the floor. That difference is the quantity of energy you must put into the leap. Conservation of energy is the principle you use to easily solve this problem.

Work at it a little more and you will be able to solve for the speed you have as your feet leave the ground.

I am able to solve it using mgh = 0.5mv^2, but this way seems to be much faster.
So my potential energy at the top is mgH, right? That says my total energy input is FC-WC, but I still don't see why this is true. Gravity is pulling down on the person at all times, so the total energy by gravity should be mgH. And in order to move, I need to put in some Force over the total distance H that exceeds gravitational force so I can have a net movement. That energy is FH. Together, that puts me at potential energy mgH. So I'm saying FH+mgH=mgH. Which means FH=0. I'm confused

anorlunda
Staff Emeritus
And in order to move, I need to put in some Force over the total distance H that exceeds gravitational force so I can have a net movement.

We are neglecting friction here, so the leap is "free fall." In free fall, you do not need force to move, you need force to accelerate/decelerate.

While the person is in the air, the only force on him is gravity and he is accelerating downward the whole time. As his feet leave the ground, he has maximum kinetic energy. The kinetic energy becomes potential energy as he ascends, reaching zero kinetic energy at the top of the leap. During the leap, the sum of kinetic plus potential energies is constant.

ok so all the energy I put in right before being airborne is my maximum kinetic energy. This energy is the force by my muscles, and in order to accelerate up, I must oppose gravitational force, and then add some more force to start to move up. So I have to put in energy WC+ FC, and that equals mgh, right? This is what I originally thought when doing my HW, but apparently it is wrong. I don't see why it is wrong.

jbriggs444