Conservation of energy of a skier

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SUMMARY

The discussion centers on the conservation of energy principles applied to a skier descending various inclined paths. The gravitational potential energy (PE) change is the same across all runs due to identical height (h), leading to the conclusion that the final kinetic energy (KE) and speed at the bottom are also the same for all paths. However, the time taken to reach the bottom varies, with the steepest path allowing the skier to descend the quickest. The equations governing this analysis include Ei = Ef and mgh = 1/2mv^2.

PREREQUISITES
  • Understanding of gravitational potential energy (PE = mgh)
  • Knowledge of kinetic energy (KE = 1/2mv^2)
  • Familiarity with the concept of energy conservation (Ei = Ef)
  • Basic principles of motion and acceleration on inclined planes
NEXT STEPS
  • Explore the effects of friction on energy conservation in skiing scenarios
  • Learn about the dynamics of inclined planes and acceleration calculations
  • Investigate the relationship between slope steepness and time of descent
  • Study real-world applications of energy conservation in sports physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators seeking to explain these concepts in practical scenarios.

brycenrg
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Homework Statement


A skier starts at the top of a friction less hill. You have 4 different runs, they have different difficulties. So I am assuming they are at different inclines. 1) longest route, not so steep 2) medium length, little steeper 3) shorter more steep 4) straight path, and very steep 5) all the same

On which run does her gravitational potential energy change the most?

On which run would her speed at the bottom be the fastest?

Which run would she get to the bottom the the quickest?

Homework Equations


Ei = Ef
mgh = 1/2mv^2

The Attempt at a Solution


Since Potential Energy = mgh
H is the same, I can assume. P converts into K
mgh = 1/2mv^2
so the final velocity will be the same for all. Kinetic energy is not a vector quantity either.
The gravitational potential energy will change the same amount in all runs.
The speed will be the same at the bottom for all runs.
She would get to the bottom the quickest at the steepest path. but would still have the same final energy or velocity/KE at the bottom.

Is this correct? for the longest time i thought they would get to the bottom at the same time but i don't think so anymore.
[/B]
 
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brycenrg said:

Homework Statement


A skier starts at the top of a friction less hill. You have 4 different runs, they have different difficulties. So I am assuming they are at different inclines. 1) longest route, not so steep 2) medium length, little steeper 3) shorter more steep 4) straight path, and very steep 5) all the same

On which run does her gravitational potential energy change the most?

On which run would her speed at the bottom be the fastest?

Which run would she get to the bottom the the quickest?

Homework Equations


Ei = Ef
mgh = 1/2mv^2

The Attempt at a Solution


Since Potential Energy = mgh
H is the same, I can assume. P converts into K
mgh = 1/2mv^2
so the final velocity will be the same for all. Kinetic energy is not a vector quantity either.
The gravitational potential energy will change the same amount in all runs.
The speed will be the same at the bottom for all runs.[/B]


Correct so far...

brycenrg said:
She would get to the bottom the quickest at the steepest path. but would still have the same final energy or velocity/KE at the bottom.

Is this correct? for the longest time i thought they would get to the bottom at the same time but i don't think so anymore.

What does your last sentence mean?

The motion of the skier can be thought as the resultant of its vertical motion and its horizontal motion. The vertical displacement h is the same for all routes. The displacement is h = a/2 t2. How does the vertical acceleration depend on the steepness of the slope?
 
What does your last sentence mean?

The motion of the skier can be thought as the resultant of its vertical motion and its horizontal motion. The vertical displacement h is the same for all routes. The displacement is h = a/2 t2. How does the vertical acceleration depend on the steepness of the slope?[/QUOTE]

If I fell off of a height of H. The force of gravity is mg
Now if I fell off a slope with 80 decline. The force of gravity is only mg(cos(10)). Is this correct way in thinking?
 

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