Conservation of energy of an oxygen molecule

  • Thread starter jincy34
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  • #1
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[SOLVED] conservation of energy

Homework Statement



From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 200 K?

Homework Equations



conservation of energy
Eavg=3/2KbT
Epot=mgh

The Attempt at a Solution



I used conservation of energy and set
Epot.=Eavg. and got 7855.8 m. But it is wrong.
 

Answers and Replies

  • #2
Shooting Star
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What is the correct ans? This one seems to be right. Or my computer's not working.
 
  • #3
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I get to see the answer only after it is due. It is due thursday. when i tried this answer, the computer says it is wrong.
 
  • #4
rl.bhat
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Eavg=3/2KbT
Oxygen molecule is a diatomic molecule. Therefore Eavg = 5/2kbT. Try this.
 
  • #5
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Thank you.
 
  • #6
Shooting Star
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Eavg=3/2KbT
Oxygen molecule is a diatomic molecule. Therefore Eavg = 5/2kbT. Try this.
Oy. Forgot about that altogether. Thanks from me too.
 

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