Conservation of energy of an oxygen molecule

1. Nov 27, 2007

jincy34

[SOLVED] conservation of energy

1. The problem statement, all variables and given/known data

From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 200 K?

2. Relevant equations

conservation of energy
Eavg=3/2KbT
Epot=mgh
3. The attempt at a solution

I used conservation of energy and set
Epot.=Eavg. and got 7855.8 m. But it is wrong.

2. Nov 27, 2007

Shooting Star

What is the correct ans? This one seems to be right. Or my computer's not working.

3. Nov 27, 2007

jincy34

I get to see the answer only after it is due. It is due thursday. when i tried this answer, the computer says it is wrong.

4. Nov 27, 2007

rl.bhat

Eavg=3/2KbT
Oxygen molecule is a diatomic molecule. Therefore Eavg = 5/2kbT. Try this.

5. Nov 28, 2007

jincy34

Thank you.

6. Nov 28, 2007

Shooting Star

Oy. Forgot about that altogether. Thanks from me too.