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Conservation of energy of an oxygen molecule

  1. Nov 27, 2007 #1
    [SOLVED] conservation of energy

    1. The problem statement, all variables and given/known data

    From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 200 K?

    2. Relevant equations

    conservation of energy
    3. The attempt at a solution

    I used conservation of energy and set
    Epot.=Eavg. and got 7855.8 m. But it is wrong.
  2. jcsd
  3. Nov 27, 2007 #2

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    What is the correct ans? This one seems to be right. Or my computer's not working.
  4. Nov 27, 2007 #3
    I get to see the answer only after it is due. It is due thursday. when i tried this answer, the computer says it is wrong.
  5. Nov 27, 2007 #4


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    Oxygen molecule is a diatomic molecule. Therefore Eavg = 5/2kbT. Try this.
  6. Nov 28, 2007 #5
    Thank you.
  7. Nov 28, 2007 #6

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    Oy. Forgot about that altogether. Thanks from me too.
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