1. The problem statement, all variables and given/known data To form a pendulum, a 0.092 kg ball is attached to one end of a rod of length 0.62 m and negligible mass, and the other end of the rod is mounted on a pivot. The rod is rotated until it is straight up, and then it is released from rest so that it swings down around the pivot.When the ball reaches its lowest point, what are (a) its speed and (b) the tension in the rod? Next, the rod is rotated until it is horizontal, and then it is again released from rest. (c) At what angle from the vertical does the tension in the rod equal the weight of the ball? (d) If the mass of the ball is increased, does the answer to (c) increase, decrease, or remain the same? 2. Relevant equations ƩFy=> t-mgcosθ = ma a= (v^2/r) ---> t-mgcosθ = m*(v^2/r) Ki+Ui= Kf+Uf 3. The attempt at a solution I have done part A and B already. But im struggling trying to figure out part C. I know, that they are asking at what angle, would t=mg(weight of the bob) so if we substitute t= mg in t-mgcosθ = ma, we get => mg-mgcosθ=m(v^2/r) in this step, the book calculated for velocity and then calculated the height. I sincerely dont know how to go about this problem. Im having trouble trying to find the height in order to apply it to the equation for conservation of energy. In the book solution, they solved it by first using Newtons second law to find V^2f . They didnt show how to solve for height. Please, can someone give an insight of possible ways i can approach this problem? Thank you in advance.