Pendulum Conservation of Energy

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Homework Help Overview

The discussion revolves around the conservation of energy in a pendulum system, specifically addressing the potential and kinetic energy transformations as the pendulum swings. Participants explore the relationships between maximum height, potential energy, and kinetic energy at various points in the pendulum's motion.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question the relationship between potential energy at maximum displacement and kinetic energy at the lowest point of the swing. There is discussion about the terms used in energy equations, particularly regarding rotational and translational kinetic energy.

Discussion Status

The discussion is ongoing, with participants sharing their thoughts on energy equations and questioning their understanding of kinetic energy in relation to angular velocity. Some participants have provided insights into the energy expressions for different positions of the pendulum, while others express confusion about the numerical outcomes of their calculations.

Contextual Notes

There are indications of potential misunderstandings regarding the definitions of kinetic energy in the context of a pendulum, particularly when considering the bob as a point mass versus a more complex object. Participants also mention algebraic difficulties and the need for clarity on energy conservation principles.

  • #31
PeroK said:
You need to post a problem. Show your calculations and we can see where you are going wrong. You seem to understand everything so I don't know what it could be!
Hi, so I tried again. I think I'm using the calculator wrong.
When I use √2gΔh = v that still doesn't work out.
But if I use a correct value for v, square it and divide it by 2 I get gΔh. So mgΔh is 1/2mv2 after all. I'm so relieved. Sorry for the trouble. And thank you all for helping me!
 
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  • #32
spsch said:
Hi, so I tried again. I think I'm using the calculator wrong.
When I use √2gΔh = v that still doesn't work out.
But if I use a correct value for v, square it and divide it by 2 I get gΔh. So mgΔh is 1/2mv2 after all. I'm so relieved. Sorry for the trouble. And thank you all for helping me!
Sounds like you need to enter it as √(2gΔh).
 

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