Pendulum Conservation of Energy

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The discussion revolves around understanding the conservation of energy in a pendulum system. The user seeks clarification on the relationship between potential energy at maximum height and kinetic energy at the lowest point of the swing. Key points include the realization that for a point mass, the kinetic energy can be expressed as either 1/2mv^2 or 1/2Iω^2, with both yielding the same results when calculated correctly. The conversation highlights the importance of accurately determining the change in height (Δh) and ensuring algebraic calculations are precise. Ultimately, the user finds relief in confirming that the energy equations do balance, reinforcing the principles of energy conservation in pendulum motion.
  • #31
PeroK said:
You need to post a problem. Show your calculations and we can see where you are going wrong. You seem to understand everything so I don't know what it could be!
Hi, so I tried again. I think I'm using the calculator wrong.
When I use √2gΔh = v that still doesn't work out.
But if I use a correct value for v, square it and divide it by 2 I get gΔh. So mgΔh is 1/2mv2 after all. I'm so relieved. Sorry for the trouble. And thank you all for helping me!
 
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  • #32
spsch said:
Hi, so I tried again. I think I'm using the calculator wrong.
When I use √2gΔh = v that still doesn't work out.
But if I use a correct value for v, square it and divide it by 2 I get gΔh. So mgΔh is 1/2mv2 after all. I'm so relieved. Sorry for the trouble. And thank you all for helping me!
Sounds like you need to enter it as √(2gΔh).
 

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