- #1

cyspope

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## Homework Statement

A 0.030-kg bullet is fired vertically at 200 m/s into a 0.15-kg baseball that is initially at rest. How high does the combined bullet and baseball rise after the collision, assuming the bullet embeds itself in the ball?

## Homework Equations

m

_{1}v

_{1}+ m

_{2}v

_{2}= (m

_{1}+ m

_{2}) v'

## The Attempt at a Solution

0.030 kg * 200 m/s + 0.15 kg * 0 m/s = (0.030 kg + 0.15 kg) v' = 6 = 0.18 v'

v' = 33.333 m/s

[tex]\Delta[/tex]

*p*= m(v

_{f}-v

_{o}) = 0.18 kg (33.333 m/s) = 5.999 = 6 kg * m/s

Ok, this is what I did so far. Even though I know the velocity of the bullet + ball, I don't know how high it went up because I think I need to know the time or acceleration to find x, which is height.

Please help me what to do next.