(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 0.028 kg bullet is fired vertically at 165 m/s into a 0.15 kg baseball that is initially at rest. How high does the combined bullet and baseball rise after the collision, assuming the bullet embeds itself in the ball?

2. Relevant equations

mv + mv = mv + mv

3. The attempt at a solution

m1 = 0.028 kg

v1 = 165 m/s

m2 = 0.15 kg

v2i = 0 m/s

(0.028 kg)(165 m/s) + (0.15 kg)(0 m/s) = (0.178 kg) vf

vf=25.96 m/s

v^{2}=vo^{2}- 2gy

25.96^{2}= - 2(9.8 m/s^{2})y

y=693.5m

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# Homework Help: Conservation of momentum: vertical shot

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