A roller coaster car starts from rest and descends 40 m before rising 20 m to the top of a hill. The passenger of mass 75 kg at the top of the hill feels a normal force of 368 N. The radius of curvature of the hill is...?
F = m * a
a = v^2/r
The Attempt at a Solution
Because we are given the force and the mass the person, I found the acceleration and set acceleration = v^2/r. Velocity isn't given so I used the kinematics equation: Vf^2 = Vi^2 + 2a(distance)
where Vi =0 and distance = 60. Once I found the velocity I went back and plugged that number into a =v^2/ r to find the radius but I'm not getting the right answer at all. Any help would be great.