A 78 kg skier starts from rest at a height of H = 29 m above the end of the ski-jump ramp (Figure 8-39). As the skier leaves the ramp, his velocity makes an angle of 28° with the horizontal. Neglect the effects of air resistance and assume the ramp is frictionless.
(a) What is the maximum height h of his jump above the end of the ramp?
m = 60 kg
H = 20 m
theta = 28
h = ?
I used the equation
Ki + Ui = Kf + Uf
(Initial/Final Kinetic + Potential Energy)
1/2mVi^2 + mgyi = 1/2mVf^2 + mgyf
1/2(0)^2 + (9.8)(20) = 1/2m(Vf)^2 + gh
But I dont know how to get Vf. Where do I use theta?