A 78 kg skier starts from rest at a height of H = 29 m above the end of the ski-jump ramp (Figure 8-39). As the skier leaves the ramp, his velocity makes an angle of 28° with the horizontal. Neglect the effects of air resistance and assume the ramp is frictionless. (a) What is the maximum height h of his jump above the end of the ramp? ____ m m = 60 kg H = 20 m theta = 28 h = ? I used the equation Ki + Ui = Kf + Uf (Initial/Final Kinetic + Potential Energy) 1/2mVi^2 + mgyi = 1/2mVf^2 + mgyf 1/2(0)^2 + (9.8)(20) = 1/2m(Vf)^2 + gh But I dont know how to get Vf. Where do I use theta?