- #1

- 9

- 0

A 78 kg skier starts from rest at a height of H = 29 m above the end of the ski-jump ramp (Figure 8-39). As the skier leaves the ramp, his velocity makes an angle of 28° with the horizontal. Neglect the effects of air resistance and assume the ramp is frictionless.

(a) What is the maximum height h of his jump above the end of the ramp?

____ m

m = 60 kg

H = 20 m

theta = 28

h = ?

I used the equation

Ki + Ui = Kf + Uf

(Initial/Final Kinetic + Potential Energy)

1/2mVi^2 + mgyi = 1/2mVf^2 + mgyf

1/2(0)^2 + (9.8)(20) = 1/2m(Vf)^2 + gh

But I dont know how to get Vf. Where do I use theta?