1. The problem statement, all variables and given/known data A small circular object with mass m and radius r has a moment of inertia given by I = cmr^2. The object rolls without slipping along the track shown in the figure. The track ends with a ramp of height R = 2.5 m that launches the object vertically. The object starts from a height H = 6.0 m. To what maximum height will it rise after leaving the ramp if c = 0.40? 3. The attempt at a solution My solution to this problem is 4.7 m. So I'm pretty sure my answer is right but the textbook indicates the answer is 5.0 m which confuses me. I applied conservation of energy from the starting point, mgH to the launch point (when it leave the ramp), mgR + 1/mv^2 + 1/2I[itex]\omega[/itex]^2 , and then solved for v obtaining 6.55m/s. Then, I used the equation v^2 = 2g(h-R), where h is the maximum height reached (note I'm pretty sure once the object leaves the ramp, it loses its rotational motion and maintains only linear motion after-though correct me if I'm wrong). Rearranging and substituting I obtain h=4.7m.