Conservation of kinetic energy and momentum in a collision

AI Thread Summary
In a collision between a white billiard ball and a stationary red billiard ball of equal mass, momentum is conserved while kinetic energy is not fully conserved due to energy loss to sound and other forms. The discussion concludes that since the red ball moves off with the same velocity as the white ball initially had, kinetic energy is considered conserved in this ideal scenario. Therefore, the correct answer is that both momentum and kinetic energy are conserved, indicating an elastic collision. However, in practical terms, some energy is lost, which is often overlooked in theoretical problems. The consensus affirms that while momentum is always conserved, kinetic energy can be treated as conserved in this specific case.
sugaJ
Messages
7
Reaction score
0
A white billiard ball collides with a stationary red billiard ball of equal mass. The white ball stops and the red ball moves off with the same initial velocity as the white ball. Which of the following statements about a collision between two billiard balls is correct?
a) As both momentum and kinetic energy are conserved, the collision is elastic.
b) As neither momentum nor kinetic energy are conserved, the collision is inelastic.
c) As momentum is conserve, but kinetic energy is not, the collision is elastic.
d) As kinetic energy, but not momentum is conserved, the collision is inelastic.

I am pretty sure that momentum is conserved. I don't think kinetic energy would be conserved (as some would be lost to sound energy etc) but if the ball leaves at the same velocity, my logic is telling me that all kinetic energy must be conserved and therefore the answer is a, but I'm not sure. It would be greatly appreciated if someone could help me out.

Cheers
 
Physics news on Phys.org
sugaJ said:
I am pretty sure that momentum is conserved.
Good. Momentum will always be conserved in a collision.
I don't think kinetic energy would be conserved (as some would be lost to sound energy etc) but if the ball leaves at the same velocity, my logic is telling me that all kinetic energy must be conserved and therefore the answer is a, but I'm not sure.
You are told that the velocity is the same, thus the final KE must equal the initial--KE is conserved. So yes, the answer is a.

But you are also correct that in reality some energy will be "lost" as sound energy, but that is a small effect typically ignored in these kinds of problems. Good thinking, though. :smile:
 
awesome thanks heeps mate.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top