How Does Relative Motion Affect Block R's Travel Distance?

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SUMMARY

The discussion focuses on the physics problem involving two blocks, L and R, with masses of 1.90 kg and 0.500 kg, respectively, released by a compressed spring on a frictionless surface. For part (a), the velocity of block R is calculated to be 6.84 m/s, leading to a travel distance of 5.472 meters over 0.800 seconds. Part (b) requires a second equation to relate the velocities of both blocks, emphasizing the importance of understanding relative motion in this context.

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norcal
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Homework Statement



"Relative" is an important word. Block L of mass mL = 1.90 kg and block R of mass mR = 0.500 kg are held in place with a compressed spring between them. When the blocks are released, the spring sends them sliding across a frictionless floor. (The spring has negligible mass and falls to the floor after the blocks leave it.)

(a) If the spring gives block L a release speed of 1.80 m/s relative to the floor, how far does block R travel in the next 0.800 s?
correct check mark m
(b) If, instead, the spring gives block L a release speed of 1.80 m/s relative to the velocity that the spring gives block R, how far does block R travel in the next 0.800 s?

Homework Equations



m1v1=m2v2

v=d/t

The Attempt at a Solution



1.9*1.8=.5*velocityR
velocityR = 6.84 m/s

d=v*time
d=(6.84)(.8)
d=5.472m

Ok, so 5.472m is the correct answer for part A but I don't know how to get part B. Any suggestions?
 
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norcal said:

Homework Statement



"Relative" is an important word. Block L of mass mL = 1.90 kg and block R of mass mR = 0.500 kg are held in place with a compressed spring between them. When the blocks are released, the spring sends them sliding across a frictionless floor. (The spring has negligible mass and falls to the floor after the blocks leave it.)

(a) If the spring gives block L a release speed of 1.80 m/s relative to the floor, how far does block R travel in the next 0.800 s?
correct check mark m
(b) If, instead, the spring gives block L a release speed of 1.80 m/s relative to the velocity that the spring gives block R, how far does block R travel in the next 0.800 s?

Homework Equations



m1v1=m2v2

v=d/t

The Attempt at a Solution



1.9*1.8=.5*velocityR
velocityR = 6.84 m/s

d=v*time
d=(6.84)(.8)
d=5.472m

Ok, so 5.472m is the correct answer for part A but I don't know how to get part B. Any suggestions?
You can use the same equation as in (a), realizing that if m1 moves left, m2 must move right. But you have 2 unknowns, v1 and v2, so you need a 2nd equation that relates v1 with v2. What is that relationship?
 

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