1. The problem statement, all variables and given/known data A two-ended "rocket" is initially stationary on a frictionless floor, with its center at the origin of an axis. The rocket consists of a central block C (of mass M=6 kg) and blocks L and R (each of mass m = 2 kg) on the left and right sides. Small explosions can shoot either of the side blocks away from block C and along the x axis. Here is the sequence; (1) At time t = 0, block L is shot to the left with a speed of 3 m/s "relative" to the velocity that the explosion gives the rest of the rocket. (2) Next, at time t = 0.8 sec, block R is shot to the right with a speed of 3 m/s "relative" to the velocity that block C then has. At t = 2.8 sec, what is the velocity of block C? 2. Relevant equations L = left, R = right, C = center, CR = center and right combined. So, MCR = MC + MR VCR = VC + VR and so on. Since it's in a closed system, and p=mv P(initial)=P(final) M(initial)V(initial) = M(final)V(final) 3. The attempt at a solution Since it starts at stationary, for the first step I went: 0=MLVL + MCRVCR 0=2kg(-3m/s) + 8VCR 6=8VCR 3/4 m/s = VCR 2nd step has block CR moving at 3/4 m/s. I want to find VC so: MCRVCR = MCVC + MRVR 8kg*(3/4 m/s) = 6kg*VC + 2kg*3m/s 6 = 6*VC + 6 0 = 6*VC 0 = VC This cannot be the correct answer. Where did I go wrong?