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Conservation of Momentum and Energy

  1. Nov 6, 2016 #1
    1. The problem statement, all variables and given/known data
    media%2F655%2F6552a508-d11e-4c8c-9c6e-5e12276b9d7f%2Fphp4Rr6Au.png

    2. Relevant equations
    Conservation of liner and angular momentum
    H1=H2
    r x M1V1= r x M2V2

    G1=G2
    M1V1=M2V2

    3. The attempt at a solution
    I've gotten an equation for the velocity of the block and clay after the impact, and I also know that when the block reaches the highest point of its arc, its linear velocity is going to be the same as the velocity of the cart. Is the momentum going to be conserved and I can say MbV1=Vtot(M1+M2+M3)
     
  2. jcsd
  3. Nov 6, 2016 #2
    It seems like that would be true. On the other hand, I'm thinking, "It seems too easy. Am I missing something?" But I can't think of what that might be.
     
  4. Nov 6, 2016 #3

    haruspex

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    Yes, and I believe that is where the hint is directed.
     
  5. Nov 7, 2016 #4
    But what about the about the change in potential energy as the arm swings upward?
     
  6. Nov 7, 2016 #5

    haruspex

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    What about it? That's energy, not momentum.
     
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