Conservation of momentum astronaut problem

Click For Summary
SUMMARY

The discussion centers on a physics problem involving the conservation of momentum, specifically related to an astronaut's propulsion unit. The astronaut has a mass of 143 kg and recoils at -0.265 m/s after ejecting gas at +30.9 m/s. The final mass of the astronaut is 167 kg, indicating that 24 kg of gas was expelled. The correct application of the conservation of momentum equation is crucial for determining the percentage of gas depleted from the propulsion unit.

PREREQUISITES
  • Understanding of conservation of momentum principles
  • Familiarity with basic physics equations, particularly p=mv
  • Knowledge of mass and velocity relationships in closed systems
  • Ability to manipulate algebraic equations for problem-solving
NEXT STEPS
  • Study the derivation and applications of the conservation of momentum in various scenarios
  • Learn how to solve problems involving mass and velocity changes in propulsion systems
  • Explore examples of momentum conservation in space mechanics
  • Investigate the effects of gas expulsion on motion in vacuum environments
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and momentum, as well as educators looking for practical examples of conservation principles in action.

pureouchies4717
Messages
98
Reaction score
0

Homework Statement


An astronaut in his space suit and with a propulsion unit (empty of its gas propellant) strapped to his back has a mass of 143 kg. During a space-walk, the unit, which has been filled with propellant gas, ejects some gas with a velocity of +30.9 m/s. As a result, the astronaut recoils with a velocity of -0.265 m/s. After the gas is ejected, the mass of the astronaut (now wearing a partially empty propulsion unit) is 167 kg. What percentage of the gas propellant in the completely filled propulsion unit was depleted?



Homework Equations



p=mv



The Attempt at a Solution


-.265(astronaut + gas) = 30.9 (gas)
-.265(143 + x) = 30.9x
-37.846 -.265x = 30.9x
31.165x = -37.846
x = 1.214 kg


i don't really know where to go from here... can someone please help?
 
Physics news on Phys.org
You need to distinguish between the portion of gas left in the propulsion unit and the portion of gas expelled. You should be able to immediately figure out the portion in the container from the data given. Use the conservation of momentum equation to find the portion expelled.
nick727kcin said:

The Attempt at a Solution


-.265(astronaut + gas) = 30.9 (gas)
Correct this equation. The "gas" on the left is the portion left in the unit, which should not be an unknown. And get rid of that minus sign on the left.
 

Similar threads

Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
15K
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K