Conservation of Linear Momentum of astronaut

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SUMMARY

The discussion centers on the conservation of linear momentum as applied to an astronaut using a propulsion unit in outer space. When the propulsion unit ejects gas at a velocity of 32 m/s, the astronaut recoils at -30 m/s with a mass of 160 kg. By applying the momentum conservation equation, the mass of the ejected gas is calculated to be 150 kg, confirming the accuracy of the calculations presented.

PREREQUISITES
  • Understanding of linear momentum and its conservation principles
  • Familiarity with basic physics equations involving mass and velocity
  • Knowledge of the concept of external and internal forces
  • Ability to solve algebraic equations
NEXT STEPS
  • Study the principles of conservation of momentum in various systems
  • Explore real-world applications of propulsion in space travel
  • Learn about the effects of mass and velocity in different physical scenarios
  • Investigate the role of external and internal forces in motion
USEFUL FOR

Students of physics, aerospace engineers, and anyone interested in the mechanics of motion in space will benefit from this discussion.

rmarkatos
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I am pretty sure i have this question correct but i want to make sure it is likely to show up on a test

An astronaut is motionless in outer space. Upon command the propulsion unit strapped to his back ejects some gas with a velocity of 32m/s and the astronaut recoils with a velocity of -30m/s. After the gas is ejected the mass of the astronaut is 160kg. What is the mass of the ejected gas?

well after looking at external and internal forces they should both equal zero.
So i found that Pf=Pi is that correct? But the initial conditions are zero because the astronaut was motionless in outer space. I am going to call m1 and vf1 the astronaut and m2 and vf2 the propulsion unit.

m1vf1+m2vf2=0

160kg(-30m/s) + m2(32m/s)=0
-4800kg m/s +m2(32m/s)=0
m2(32m/s)=4800kg m/s

solving for m2 i got 150kg. is that correct?
 
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Yes, appears correct.
 

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