Conservation of Momentum (Ch 7-9, Q6)

Click For Summary
SUMMARY

The discussion focuses on the conservation of momentum in the context of a bomb exploding in space, where the net gravitational force is zero. The correct answers to the posed statements are that the vector sum of the linear momenta of the fragments must be zero, and the velocity of any fragment must be equal to the velocity of any other fragment, which is zero immediately after the explosion. Kinetic energy is not conserved during the explosion as it transforms into heat and kinetic energy of the fragments. The fragments do not possess equal kinetic energies post-explosion due to their varying trajectories.

PREREQUISITES
  • Understanding of the Conservation of Momentum principle
  • Basic knowledge of kinetic and potential energy concepts
  • Familiarity with Newton's laws of motion
  • Concept of explosions in a vacuum environment
NEXT STEPS
  • Study the principles of Conservation of Energy in explosive events
  • Learn about the effects of explosions in a vacuum
  • Explore the relationship between mass, velocity, and momentum
  • Investigate real-world applications of momentum conservation in physics
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in understanding the principles of momentum and energy transformations during explosive events.

gcombina
Messages
157
Reaction score
3

Homework Statement


A stationary bomb explodes in space breaking into a number of small fragments. At the location of the explosion, the net force due to gravity is zero Newtons. Which one of the following statements concerning this event is true?
(a) Kinetic energy is conserved in this process.

(b) The fragments must have equal kinetic energies.

(c) The sum of the kinetic energies of the fragments must be zero.

(d) The vector sum of the linear momenta of the fragments must be zero.

(e) The velocity of anyone fragment must be equal to the velocity of any other fragment.

Homework Equations


Conservation of Momentum
(mv) before = mv (after)

The Attempt at a Solution



(a) Kinetic energy is conserved in this process.
This is a NO, because Kinetic energy isn't conserved, the energy is lost
(b)
The fragments must have equal kinetic energies
I assume the fragments do not longer have Kinetic energy but Potential energy so its a NO
(c)
The sum of the kinetic energies of the fragments must be zero.
Fragments do not longer have Kinetic energy as they are stationary, they have potential energy (I have no clue if this reasoning is correct) so the answer is NO
(d) The vector sum of the linear momenta of the fragments must be zero.
mass and velocity = 0 so Yes
(e) The velocity of anyone fragment must be equal to the velocity of any other fragment.
The velocity is ZERO so they all have the same velocity so the answer is YES to this too (Is this correct? like some fragments can be having a velocity of 0 and others can have some movement still)
 
Physics news on Phys.org
You need to rethink what is going on here. Before the bomb explodes it is sitting stationary, so no kinetic energy. After it explodes, whatever energy powers the bomb (chemical, atomic,...) is turned into heat and kinetic energy of the fragments. The fragments scatter in all directions. Because the explosion takes place in space far from any large gravitational forces and without any friction to slow anything down, the fragments will all continue to travel indefinitely along straight paths.
 
I see, that is why they said 0 gravity...brb
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
4K
Replies
15
Views
2K
  • · Replies 3 ·
Replies
3
Views
7K
Replies
4
Views
2K
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
55
Views
6K
Replies
10
Views
3K
Replies
13
Views
3K
Replies
17
Views
2K