Conservation of Momentum in a Girl and Plank System

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Homework Help Overview

The problem involves a girl walking on a plank that is free to slide on a frictionless surface, raising questions about the conservation of momentum in a two-body system. The scenario includes a girl with a mass of 45.0 kg and a plank with a mass of 156 kg, both initially at rest, and the girl walks at a velocity of 1.51 m/s relative to the plank.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of the conservation of momentum equation and question the interpretation of velocities relative to different frames of reference. There is an exploration of how to define variables for the velocities of both the girl and the plank relative to the ice.

Discussion Status

The discussion is ongoing, with participants attempting to clarify the definitions of variables and the relationships between the velocities of the girl and the plank. Some guidance has been offered regarding the need to define unknowns for the various velocities and to establish equations based on those definitions.

Contextual Notes

Participants note that the velocities of the girl and the plank must sum to the specified relative velocity of 1.51 m/s, raising questions about the assumptions made in the initial setup and calculations.

ngorecki
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conservation of momentum??

Homework Statement



A 45.0 kg girl is standing on a 156 kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.51 m/s relative to the plank.

(a) What is her velocity relative to the ice surface?
(b) What is the velocity of the plank relative to the ice surface?

variable:
girl=45kg
plank=156kg
Vi=0m/s
Vf=1.51m/s

Homework Equations



mavai + mbvbi = mavaf +mbvbf

The Attempt at a Solution



since Vi=0m/s left side of consercation of momentum equation =0
0 = 45(Vf) + 156(1.51)
0 = 45(Vf) + 235.56
-235.56 = 45(Vf)
-5.23 = Vf

this answer is not possible because the absolute value of part a and b should add up to 1.51 while 5.23 is already much bigger

 
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sorry for putting the blank template 2X below...didnt see that before posting
 


ngorecki said:
[
A 45.0 kg girl is standing on a 156 kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.51 m/s relative to the plank.

(a) What is her velocity relative to the ice surface?
(b) What is the velocity of the plank relative to the ice surface?

variable:
girl=45kg
plank=156kg
Vi=0m/s
Vf=1.51m/s
What is your Vf here? How about putting in some variables for speeds of girl and plank relative to the ice?
 


haruspex said:
What is your Vf here? How about putting in some variables for speeds of girl and plank relative to the ice?

Vf = 1.51 m/s

and the question is asking what the speeds are... Which I am struggling to solve. How do you suggest I go about soving for the speeds?
 


ngorecki said:
Vf = 1.51 m/s
No, I mean what does it represent?
and the question is asking what the speeds are... Which I am struggling to solve. How do you suggest I go about soving for the speeds?
So put in variables to represent them.
 


Vf represents the total velocity at the end. The velocity relative to the ice for the girl and the plank added together should equal the Vf (1.51)
 


ngorecki said:
Vf represents the total velocity at the end. The velocity relative to the ice for the girl and the plank added together should equal the Vf (1.51)
That isn't what you are given: "The girl begins to walk along the plank at a constant velocity of 1.51 m/s relative to the plank."
Define unknowns for the various velocities relative to the ice and see what equations you can write using them.
 

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