Linear Momentum - Person on a Plank on a frictionless surface

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Homework Help Overview

The problem involves a plank on a frictionless surface with a girl walking from one end to the other. The discussion centers on understanding the implications of linear momentum and the movement of the plank in relation to the girl's movement.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the necessity of knowing the girl's velocity to solve the problem and explore the concept of the center of mass of the system. Questions arise about how to calculate the plank's shift without this information.

Discussion Status

Some participants have offered insights into the concept of the center of mass and its relevance to the problem. There is an ongoing exploration of how the plank and the girl move in relation to each other, with some participants expressing uncertainty about the next steps in their reasoning.

Contextual Notes

Participants are working under the assumption that the forces involved are internal to the system, and the initial and final momentum must balance. There is a focus on the positions of the center of mass before and after the girl's movement.

crafty2288
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Homework Statement


A plank of length 6m is lying on a smooth horizontal surface and has a mass of 100kg. A 50kg girl walks from one end of the plank to the other. In this experiment, how far will the plank shift and what direction? Why?

Homework Equations


v_g will mean girl's velocity relative to ice.
v_p will mean plank's velocity relative to ice.
M(girl)V(girl)[initial] + M(plank)V(plank)[initial] = M(girl)V(girl)[final] + M(plank)V(plank)[final]

The Attempt at a Solution



I feel like I need the girl's velocity or I can't do this. I understand how to solve it, but can anyone help me to understand how I do it without knowing the girl's velocity?

Initial momentum = 0 (because she's at rest).
Final momentum = 0 (because it has to equal initial momentum)

M(girl)V(girl)[initial] + M(plank)V(plank)[initial] = M(girl)V(girl)[final] + M(plank)V(plank)[final]
0 + 0 = (50)*V(girl)f + (100)*V(plank)fOr am I making this harder than it needs to be?
 
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The essence of this problem is that since all forces involved are internal to the system, the center of mass of the system (plank plus girl) does not move even though the girl and the plank do move. The velocity of the girl or the plank is immaterial, {though as a practical matter, she should move slowly :) }
 
AEM said:
The essence of this problem is that since all forces involved are internal to the system, the center of mass of the system (plank plus girl) does not move even though the girl and the plank do move. The velocity of the girl or the plank is immaterial, {though as a practical matter, she should move slowly :) }

Sorry... I'm not sure where to go from here then... The Plank clearly will move, so how then do i calculate it?
 
Okay, draw a picture of the girl on the plank. Label the girl's center of mass. Label the plank's center of mass. Look up how to calculate the center of mass of the girl + plank. That point doesn't move. However, the girls and the plank DO move. They have to move so that in their final position their combined center of mass is in the same place. Stare at your drawing a little while, and the answer should hit you.
 
(Assuming that you are looking at the Plank from the side, and the girl starts at the left. Left being 0m, Right being 6m.)

So the center of mass before the move is at 2m...

And the center of mass after the move is at 4m...Does this mean that in relation to the surface... The plank has shifted 2m to the left?
 
crafty2288 said:
(Assuming that you are looking at the Plank from the side, and the girl starts at the left. Left being 0m, Right being 6m.)

So the center of mass before the move is at 2m...

And the center of mass after the move is at 4m...


Does this mean that in relation to the surface... The plank has shifted 2m to the left?



That looks right to me.
 

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